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4 years ago

You measure the voltage difference of a circuit to be 15 Volts and the resistance to be 675 Ohms.

Physics

1 answer:

ser-zykov [4K]4 years ago

5 0

Answer:

0.0222 A

Explanation:

V = I*R

$15v = 675ohms \times i \\ i = \frac{15v}{675ohms} = 0.0222 a$

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podryga [215]

Explanation:

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I hope this is the correct way to solve

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3 years ago

A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien

n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

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$\phi=NBA$

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$\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2$

$\phi=7.85\times10^{-7}\ Tm^2$

We need to calculate the induced emf

Using formula of induced emf

$\epsilon=\dfrac{d\phi}{dt}$

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$\epsilon=\dfrac{7.85\times10^{-7}}{dt}$

Put the value of emf from ohm's law

$\epsilon =IR$

$IR=\dfrac{7.85\times10^{-7}}{dt}$

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$Idt=\dfrac{7.85\times10^{-7}}{0.50}$

$Idt=0.00000157=1.57\times10^{-6}\ C$

We know that,

$Idt=dq$

$dq=1.57\times10^{-6}\ C$

We need to calculate the voltage across the capacitor

Using formula of charge

$dq=C dV$

$dV=\dfrac{dq}{C}$

Put the value into the formula

$dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}$

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3 years ago

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liq [111]

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3 years ago

How many photons are absorbed during the dental x-ray?

MariettaO [177]

<span>E=hc/wav. len
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E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
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Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
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