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denis23 [38]
3 years ago
15

A segment of wire carries a current of 25 A along the x axis from x = −2.0 m to x = 0 and then along the z axis from z = 0 to z

= 3.0m. In this region of space, the magnetic field is equal to 40 mT in the positive z direction. What is the magnitude of the force on this segment of wire?
Physics
1 answer:
katrin [286]3 years ago
8 0

Answer:

F_x=2N

Explanation:

The force on this segment is given by:

F=I*(\beta x L)

In the axis z'

F_z=I*(\beta x L_z)

\beta x L_z=\beta *L*sin(0)=40mT*3.0m*0=0

So the force is zero in the axis z' because the normal is in the same axis of the magnetic field

In the axis x'

F_x=I*(\beta x L_x)

\beta x L_x=\beta *L*sin(90)=40mT*-2.0m*1

F_x=25A*80x10^{-3}T*m

F_x=2N

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PLZ HELP ON #22-26!!!! <br><br>Please explain why and how you got your answer.
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I hope this helps!! 

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