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xxMikexx [17]
3 years ago
14

Six years less than Tracy's age write it as a algebratic expression

Mathematics
2 answers:
Lostsunrise [7]3 years ago
5 0

T = Tracy's age.

We will use the letter T, because we have no clue what Tracy's age is. And most algebraic expressions have letters related to the problem. We know that Tracy is older than 6 so we have to do T - 6 we know this is subtraction due to the word "less than" so you algebraic expression/answer is T - 6. I hope my answer was a pretty understanding and that you get it now! :D




~ A friendly helper!

docker41 [41]3 years ago
3 0
 the answer would for the equation would beT-6 or 6-T
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For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?
STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

z=\frac{x-\mu}{\sigma}

Top 60% means greater than 40%.

Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of -0.25.

Upon substituting our given values in z-score formula, we will get:

-0.25=\frac{x-500}{100}

-0.25*100=\frac{x-500}{100}*100

-25=x-500

-25+500=x-500+500

x=475

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

3 0
3 years ago
What is the value of u and v?
Novay_Z [31]

Answer and Explanation:

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u = v = 164√2 / √2 = 164

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u = 164

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3 0
2 years ago
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What are the numbers after 10 8 7 9​
kramer

Answer:

Step-by-step explanation:

ven numbers always end with a digit of 0, 2, 4, 6 or 8.

2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30 are even numbers.

Odd numbers always end with a digit of 1, 3, 5, 7, or 9.

1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 are odd numbers.

3 0
3 years ago
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wariber [46]
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Elis [28]

Answer: 32

Step-by-step explanation:

Given: The energy needed for 1 hour of running for an adult =4.5\times10^6\ joules.

Therefore. the energy needed for seven hours of running==7\times4.5\times10^6\ joules.=31.5\times10^6\ joules

Since, he energy released by metabolism of 1 average candy bar =1\times10^6\ joules.

Therefore, the number of candy bars an adult need to eat  to supply the energy needed for seven hours of running.=\frac{31.5\times10^6}{1\times10^6}=31.5\approx32

Hence, the adult need to eat 32 candies to supply the energy needed for seven hours of running.

3 0
3 years ago
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