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2 years ago

Six years less than Tracy's age write it as a algebratic expression

Mathematics

2 answers:

Lostsunrise [7]2 years ago

5 0

T = Tracy's age.

We will use the letter T, because we have no clue what Tracy's age is. And most algebraic expressions have letters related to the problem. We know that Tracy is older than 6 so we have to do T - 6 we know this is subtraction due to the word "less than" so you algebraic expression/answer is T - 6. I hope my answer was a pretty understanding and that you get it now! :D

~ A friendly helper!

docker41 [41]2 years ago

3 0

the answer would for the equation would beT-6 or 6-T

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2 years ago

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3 years ago

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2 years ago

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Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first three terms is 26.

Serga [27]

Answer:

<h3>The nth term Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>

Step-by-step explanation:

Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.

If the sum of the first two term is 24, then a/r + a = 24...(1)

and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)

Substtituting equation 1 into 2 we have;

24+ar = 26

ar = 2

a = 2/r ...(3)

Substituting a = 2/r into equation 1 will give;

(2/r))/r+2/r = 24

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4r(3r-1)+1(3r-1) = 0

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r = -1/4 0r 1/3

Since a= 2/r then a = 2/(-1/4)or a = 2/(1/3)

a = -8 or 6

All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of a geometric sequence is expressed as

if r = -1/4 and a = -8

Tn = -8(-1/4)^(n-1)

if r = 1/3 and a = 6

Tn = 6(1/3)^(n-1)

The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms

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