Six years less than Tracy's age write it as a algebratic expression
2 answers:
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Bus riders: 2c
Car riders: c
Walkers: 1/5c
Bus + Car + Walkers = Total
2c + c + 1/5c = 32
3c = 32
c = 32
c = 32 (
c = 10
Bus: 2c = 2(10) = 20
Walkers: c =
(10) = 2
Answer: Bus riders=20, Car riders=10, Walkers=2
The equation represent a linear relation with the y-intercept
representing the amount of initial fee.
Correct response:
1. 28 volleyball uniforms
2. Price per uniform
3. Initial flat order fee
4. 10 fewer volleyball uniform
<h3>Methods used for finding the above values</h3>The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35
Where;
C = The uniform costs
n = The number of volleyball uniform ordered
The maximum amount the school has to spend = $600
1. The number of uniforms the school can buy is given by setting C = 600 as follows;
- C = 20·n + 35
Therefore;
600 = 20·n + 35
20·n = 600 - 35 = 565
Rounding down to the nearest whole number, we have;
- The number of uniforms the school can buy, n = <u>28 volleyball uniforms</u>.
2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;
- 20 represents a <u>$20 price per uniform</u>.
3. The 35 in the equation represents an initial <u>flat fee</u>, such as an
ordering or initial fee, which is fixed.
Therefore;
- The number 35 represent the <u>fixed cost </u>for producing the uniforms
4. The price per uniform of $30 changes the coefficient of <em>n</em> from 20 to 30 as follows;
C = 30·n + 35
The number of uniforms the school can by with $600 is therefore;
Which gives;
The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms
The difference in the number of uniforms purchased = 28 - 18 = 10
Therefore;
- The school can purchase <u>10 fewer uniforms</u> at $30 per uniform
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