Answer:
a = 17.68 m/s²
Explanation:
given,
length of the string, L = 0.8 m
angle made with vertical, θ = 61°
time to complete 1 rev, t = 1.25 s
radial acceleration = ?
first we have to calculate the radius of the circle
R = L sin θ
R = 0.8 x sin 61°
R = 0.7 m
now, calculating at the angular velocity


ω = 5.026 rad/s
now, radial acceleration
a = r ω²
a = 0.7 x 5.026²
a = 17.68 m/s²
hence, the radial acceleration of the ball is equal to 17.68 rad/s²
C i would think
it sounds best
Answer:
When deformed, it returns to its original shape
Explanation:
- A spring is elastic.
- Elasticity is the property of a material to regain its shape after having been deformed.
- It means that when the force is doubled, the amount of deformation in it gets doubled.
- Hence, the correct option is (b) " When deformed, it returns to its original shape".
Answer:
B
Explanation:
If you cross of what you don't think are the answers then it makes it easier to narrow it down to what the answers are.
Hope this helps!