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Sholpan [36]
3 years ago
14

Suppose that during any period of ¼ second there is one instant at which the crests or troughs of component waves are exactly in

phase and maximum reinforcement occurs. How many beats will occur in 1 second? A. 4
B. 8
C. 12
D. 2
Physics
1 answer:
kolezko [41]3 years ago
6 0
<h3><u>Answer;</u></h3>

A. 4

<h3><u>Explanation;</u></h3>
  • <em><u>The period of a wave or periodic time is the time taken for a complete oscillation to occur. </u></em>For example its is the time taken between two successive crests or troughs.
  • <em><u>The beats or oscillation that occur in one second represents the frequency. Frequency is the number of complete oscillations or beats in one second in a wave.</u></em>
  • Frequency, measured in Hertz is given by the reciprocal of the periodic time.
  • Thus; <u><em>Frequency or beats per second = 1/(1/4) = 4</em></u>
  • <u><em>Hence , 4 beats per second</em></u>

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Hi there!

The average speed (a.s) is calculated by dividing the traveled distance (d) over the time needed to travel that distance (t):

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So, let´s find the distance traveled in those 3 s. For that, we can use the equation of position of an object moving in a straight line with constant acceleration:

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Where "v" is the velocity at a time "t". Since v0 = 0, then:

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