Possible beat frequencies with tuning forks of frequencies 255, 258, and 260 Hz are 2, 3 and 5 Hz respectively.
The beat frequency refers to the rate at which the volume is heard to be oscillating from high to low volume. For example, if two complete cycles of high and low volumes are heard every second, the beat frequency is 2 Hz. The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 256 Hz and 254 Hz are played simultaneously, a beat frequency of 2 Hz will be detected. A common physics demonstration involves producing beats using two tuning forks with very similar frequencies. If a tine on one of two identical tuning forks is wrapped with a rubber band, then that tuning forks frequency will be lowered. If both tuning forks are vibrated together, then they produce sounds with slightly different frequencies. These sounds will interfere to produce detectable beats. The human ear is capable of detecting beats with frequencies of 7 Hz and below.
A piano tuner frequently utilizes the phenomenon of beats to tune a piano string. She will pluck the string and tap a tuning fork at the same time. If the two sound sources - the piano string and the tuning fork - produce detectable beats then their frequencies are not identical. She will then adjust the tension of the piano string and repeat the process until the beats can no longer be heard. As the piano string becomes more in tune with the tuning fork, the beat frequency will be reduced and approach 0 Hz. When beats are no longer heard, the piano string is tuned to the tuning fork; that is, they play the same frequency. The process allows a piano tuner to match the strings' frequency to the frequency of a standardized set of tuning forks.
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Yes i think so im pretty sure
Radius of the circular loop is 0.0091m.
<h3>What is magnetic field?</h3>
Magnetic field is the area around a magnet where the magnetism influence is felt .
<h3>What is the magnetic field at the centre of a circular loop?</h3>
- The formula for magnetic field at the centre of a loop is
B =(μ)I/2r
- where B= Magnetic field at the centre of a circular loop
μ= Magnetic permeability =4(π)*10^(-7)
I= current flowing through the loop
r= radius of the loop
- Thus, radius of the loop =(4(π)×10^(-7)×5.7)/(2×3.9×10^(-4))
=0.0091m
Thus, we can conclude that the radius of the loop is 0.0091m .
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<span>The force that an object feels in an electric field is the magnitude of the electric field E times the charge on the object Q.
We know that the magnitude of the charge of an electron is 1.6 x 10^{-19} C
F = E x Q
E = F / Q
E = (3.5 x 10^{-16} N) / (1.6 x 10^{-19} C)
E = 2.19 x 10^3 N/C
The magnitude of the electric field at the location of the electron is 2.19 x 10^3 N/C</span>
C. Farmers and gardeners should use other methods..........
