As long as the net force on a falling object is not zero, the object will...
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<h2>Answer:</h2>
0.5Ω
<h2>Explanation:</h2>Since different currents are passing through the resistors, then the resistors are most probably connected in parallel. This also means that the same voltage will pass across them.
Using Ohm's law, the voltage across a resistor in a circuit is given by;
V = I(R + r) -----------(i)
<em>For the 1ohm resistor, the voltage across it is given by;</em>
<em>Where;</em>
I = current passing through the 1 ohm resistor = 0.6A
R = resistance of the 1 ohm resistor = 1Ω
r = internal resistance of the cell = r
Substitute these values into equation (i) as follows;
V = 0.6(1 + r) -------------------(ii)
<em>For the 4.0ohm resistor, the voltage across it is given by;</em>
<em>Where;</em>
I = current passing through the 4.0 ohms resistor = 0.2A
R = resistance of the 4.0 ohms resistor = 4.0Ω
r = internal resistance of the cell = r
Substitute these values into equation (i) as follows;
V = 0.2(4.0 + r) -------------------(iii)
<em>Now solve equations (ii) and (iii) simultaneously;</em>
V = 0.6(1 + r)
V = 0.2(4.0 + r)
Substitute the value of V in equation (ii) into equation (iii). Therefore, we have;
0.6(1 + r) = 0.2(4.0 + r)
<em>Solve for r</em>
0.6 + 0.6r = 0.8 + 0.2r
0.6r - 0.2r = 0.8 - 0.6
0.4r = 0.2
r =
r = 0.5
Therefore, the internal resistance of the cell is 0.5Ω
Answer:
The speed with which the skier was going is approximately 2.9906 m/s
Explanation:
The given parameters are;
The distance the skier slides before coming to rest, s = 12.4 m
The coefficient of friction between the skier and the snow, = 0.0368
Therefore, for conservation of energy, we have;
Initial kinetic energy = Work done by the kinetic friction force
Initial kinetic energy = 1/2·m·v²
The work done by the kinetic friction force = ×m×g×s
Where;
m = The mass of the skier
v = The speed with which the skier was going
g = The acceleration due to gravity = 9.8 m/s²
s = The distance the skier slides before coming to rest = 12.4 m
= The kinematic friction = 0.0368
Therefore, for conservation of energy, we have;
1/2·m·v² = ×m×g×s
1/2·v² = ×g×s
v² = 2××g×s = 2 × 0.0368 × 9.8 × 12.4 = 8.943872
v = √(8.943872) ≈ 2.99063070271 ≈ 2.9906 m/s
The speed with which the skier was going = v ≈ 2.9906 m/s.