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Nikitich [7]
3 years ago
9

How and why planets orbit the sun and how and why a planets speed changes orbit

Physics
2 answers:
anygoal [31]3 years ago
7 0

the gravitonal pull

Explanation:

Brut [27]3 years ago
5 0

The details are very long and complicated. The simplest way I can answer those 4 questions is: That's the way gravity works.

If you take Newton's law of gravity and his three laws of motion, and massage them properly using some geometry and some calculus, you can show that planets MUST move like Kepler's laws say they do, and like what we see them actually doing in the sky.

(I used to be able to do this, but it's been a while.)

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4 years ago
A proposed answer to a scientific problem is a _.
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3 years ago
The earth rotates every 86,160 seconds. What is the tangential speed (in m/s) at Livermore (Latitude 37.6819° measured up from e
Lena [83]

Answer:

The tangential speed at Livermore is approximately 284.001 meters per second.

Explanation:

Let suppose that the Earth rotates at constant speed, the tangential speed (v), measured in meters per second, at Livermore (37.6819º N, 121º W) is determined by the following expression:

v = \left(\frac{2\pi}{\Delta t}\right)\cdot R \cdot \sin \phi (1)

Where:

\Delta t - Rotation time, measured in seconds.

R - Radius of the Earth, measured in meters.

\phi - Latitude of the city above the Equator, measured in sexagesimal degrees.

If we know that \Delta t = 86160\,s, R = 6.371\times 10^{6}\,m and \phi = 37.6819^{\circ}, then the tangential speed at Livermore is:

v = \left(\frac{2\pi}{86160\,s} \right)\cdot (6.371\times 10^{6}\,m)\cdot \sin 37.6819^{\circ}

v\approx 284.001\,\frac{m}{s}

The tangential speed at Livermore is approximately 284.001 meters per second.

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3 years ago
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the answer is B

Explanation:

edg 2020

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