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tatiyna
4 years ago
11

Resistance training should be performed every day for maximum conditioning benefits.

Physics
2 answers:
marysya [2.9K]4 years ago
7 0

Answer:

The answer is True

Tanzania [10]4 years ago
7 0

Answer: The answer is false. I don't know why my comment was deleted but the answer that was wrong wasn't deleted. I had this question

Explanation:

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A weight of 1400 pounds is suspended from two cables as shown in the figure. What is the tension in the left cable? _________ po
juin [17]

Answer:

Following are the solution to this question:

Explanation:

Law:

\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}

      = 180^{\circ}- 75^{\circ}\\\\= 105^{\circ}

\to \frac{T_{L}}{\sin (90+50)}= \frac{T_{R}}{\sin (25+90)}=\frac{1400}{\sin (105)}

\to T_L=931.65 \ pounds \\\\ \to T_R=1313.59 \ pounds \\\\

4 0
3 years ago
Which one of the following is not a fundamental physical quantity? a) Time c) Force b) Mass d) Length ​
Klio2033 [76]

Answer:

D

Explanation:

5 0
3 years ago
PLEASE !! Help
n200080 [17]

Answer:

scalar,magnitude

Explanation:

scalar is an example of length/distance

magnitude is the length of a vector

8 0
3 years ago
A wire coil inside a generator has 150 square loops and an area equal to 0.042 m2.
Anna [14]

D. The maximum electromotive force induced in the coil is determined as 3,200 V.

<h3>Maximum electromotive force induced in the coil</h3>

emf(max) = NAB/t

where;

  • N is number of turns
  • B is magnetic field
  • A is area of the coil
  • t is time

Substitute the given parameters and solve for emf

emf(max) = (150 x 0.042 x 0.86) / (1.7 x 10⁻³)

emf(max) = 3,187.1 V

emf(max) ≈ 3,200 V

Thus, the maximum electromotive force induced in the coil is determined as 3,200 V.

Learn more about emf here: brainly.com/question/24158806

#SPJ1

3 0
2 years ago
A parachutist with a camera, both descending at a speed of 10.8 m/s, releases that camera at an altitude of 60 m. In this proble
Masja [62]

Answer:

<em>The velocity of the camera just before it hit the ground = 35.97 m/s.</em>

Explanation:

Velocity: This can be defined as the ratio of the displacement of a body to the time. Velocity is a vector quantity, and as such it can be represented both in magnitude and direction.

From the equation of motion,

v² = u² + 2gs ................ Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.

Note: Before the velocity of the camera before it hits the ground = The final velocity of the camera.

<em>Given: u = 10.8 m/s, s = 60 m. g = 9.81 m/s.</em>

<em>Substituting into equation 1,</em>

<em>v² = 10.8² + 2(9.81)(60)</em>

<em>v² = 116.64+1177.2</em>

<em>v² = 1293.84 </em>

<em>v = √(1293.84)</em>

<em>v = 35.97 m/s.</em>

<em>Hence the velocity of the camera just before it hit the ground = 35.97 m/s.</em>

6 0
3 years ago
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