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brilliants [131]
3 years ago
8

An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir

cuit that "clicks" in response to current. The faster the current, the more clicks per minute. In this experiment, the number of clicks in one minute is recorded for each color of light shining on the photocell. To change the color of light, a different color of cellophane is placed over the same flashlight and the flashlight is then located a specific distance from the photocell.
Which of the following would be the best hypothesis for this experiment?
Chemistry
2 answers:
mart [117]3 years ago
8 0

Answer:hey! The answer is the color of light after it has passed through to cellophane

Explanation:

tamaranim1 [39]3 years ago
3 0

The light intensity. The transparency of the filter, the bandwidth of the filter,  

Also the color temperature of light source

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The amount of gas that occupies 36.52 L at 68.0°C and 672 mm Hg is __________ mol.
ASHA 777 [7]
We assume that this gas is an ideal gas. We use the ideal gas equation to calculate the amount of the gas in moles. It is expressed as:

PV = nRT
(672) (1/760) (36.52) = n (0.08206) ( 68 +273.15)
n = 1.15 mol of gas

Hope this answers the question. Have a nice day.
7 0
3 years ago
If a sample is thought to be several million years old, which method would best help to determine its absolute age?
Makovka662 [10]
The answer is B)Ar-40/k-40
6 0
3 years ago
Explain why the male angler fish is small and does not require a fully formed gut
Arturiano [62]

Answer:They are small because they don't need larger bodies to enable them attach to the females. They don't have fully formed gut because when they reach adulthood their digestive system stops functioning.

Explanation:they then find a female angler fish, attach by bitting into her flesh and fusing to her body. So whatever she eats they eat too.

3 0
3 years ago
What is the wavelength if the frequency is 29.2 hz?
ZanzabumX [31]

Answer : The wavelength is 1.027\times 10^7m

Solution : Given,

frequency = 29.2 Hz

Formula used :

\nu=\frac{c}{\lambda}\\\lambda=\frac{c}{\nu}

where,

\nu = frequency

\lambda = wavelength

c = speed of light = 3\times 10^8m/s

Now put all the given values in this formula, we get the wavelength.

\lambda=\frac{3\times 10^8m/s}{29.2Hz}=0.1027\times 10^8m=1.027\times 10^7m                 (1Hz=1s^{-1})

Therefore, the wavelength is 1.027\times 10^7m

8 0
3 years ago
The rock in a lead ore deposit contains 89 % PbS by mass. How many kilograms of the rock must be processed to obtain 1.5 kg of P
Zolol [24]

Answer:

Approximately 1.9 kilograms of this rock.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Pb: 207.2;
  • S: 32.06.

To answer this question, start by finding the mass of Pb in each kilogram of this rock.

89% of the rock is \rm PbS. There will be 890 grams of \rm PbS in one kilogram of this rock.

Formula mass of \rm PbS:

M(\mathrm{PbS}) = 207.2 + 32.06 = 239.26\; g\cdot mol^{-1}.

How many moles of \rm PbS formula units in that 890 grams of \rm PbS?

\displaystyle n = \frac{m}{M} = \rm \frac{890}{239.26} = 3.71980\; mol.

There's one mole of \rm Pb in each mole of \rm PbS. There are thus \rm 3.71980\; mol of \rm Pb in one kilogram of this rock.

What will be the mass of that \rm 3.71980\; mol of \rm Pb?

m(\mathrm{Pb}) = n(\mathrm{Pb}) \cdot M(\mathrm{Pb}) = \rm 3.71980 \times 207.2 = 770.743\; g = 0.770743\; kg.

In other words, the \rm PbS in 1 kilogram of this rock contains \rm 0.770743\; kg of lead \rm Pb.

How many kilograms of the rock will contain enough \rm PbS to provide 1.5 kilogram of \rm Pb?

\displaystyle \frac{1.5}{0.770743} \approx \rm 1.9\; kg.

5 0
3 years ago
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