What waves are utilized to sterilize medical equipment?

Which of the following statements correctly describe the trends in ionic size?

8_murik_8 [283]

the spin quantum number has values+1212 of -1212 describes the trends in ionic size.

spin quantum is denoted by (s) as it represents the electronic configuration of the atom and the ionic size also depends on the electronic configuration of the sub-shells of the atom like l, m, n, s.

ionic size increases as the electronic configuration increases because the electron adds as we move up to a higher atomic number

all the other quantum numbers may vary from atom to atom but the spin quantum number remains either +1212 or -1212. it also describes the orientation of the electrons in an atom and the axis of electrons in an atom.

learn more about quantum number here;

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8 0

3 months ago

Convert 4.92 L of hydrogen at STP to moles.

Lorico [155]

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$\sf C) \: 0.220 \: mol \: H_2$

Explanation:

1 mol = 22.4 litres

4.92 = how many moles?

$\sf \implies \frac{4.92}{22.4} \\ \\ \sf \implies 0.2196 \\ \\ \sf \implies 0.220 \: mol \: H_2$

5 0

1 year ago

Read 2 more answers

All of the following are examples of electrolytic solutions, except __.

yawa3891 [41]

The answer is B) pure water because pure water is a poor conductor of electricity.. thus a poor electrolyte

4 0

2 years ago

Read 2 more answers

To prepare an acetic acid/acetate buffer, a technician mixes 30.6 mL of 0.0880 acetic acid and 21.6 mL of 0.110 sodium acetate i

enyata [817]

Answer: There are 0.00269 moles of acetic acid in buffer.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}$ .....(1)

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

Putting values in equation 1, we get:

$0.0880M=\frac{\text{Moles of acetic acid}\times 1000}{30.6ml}\\\\\text{Moles of acetic acid}=\frac{0.0880\times 30.6}{1000}=0.00269mol$

Thus there are 0.00269 moles of acetic acid in buffer.

8 0

2 years ago

Be sure to answer all parts. Consider the following balanced redox reaction (do not include state of matter in your answers): 2C

timurjin [86]

Answer:

The specie which is oxidized is:- $CrO_2^-$

The specie which is reduced is:- $ClO^-$

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

For the given chemical reaction:

$2CrO_2^- + 6ClO^- + 2H_2O\rightarrow 2CrO_4^{2-} + 3Cl_2 + 4OH^-$

The half cell reactions for the above reaction follows:

Oxidation half reaction: $CrO_2^- + 2H_2O + 4OH^-\rightarrow CrO_4^{2-} + 4H_2O + 3e^-$

Reduction half reaction: $2ClO^- + 4H_2O + 2e^-\rightarrow Cl_2 + 2H_2O + 4OH^-$

Thus, the specie which is oxidized is:- $CrO_2^-$

The specie which is reduced is:- $ClO^-$

8 0

3 years ago