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3 years ago

Why do we not see a lunar

Chemistry

1 answer:

Nitella [24]3 years ago

4 0

Answer:

The moon's path around Earth is tilted compared to Earth's orbit around the sun. The moon can be behind Earth but still get hit by light from the sun. In this diagram, you can see that the moon's orbit around Earth is at a tilt. This is why we don't get a lunar eclipse every month.

So, I think it is A.

Explanation:

I hope that helps. I don't know if it is right or wrong, but good luck :)

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How do sulfur and phosphorus move from the biotic to the abiotic pools during their cycle?

cluponka [151]

There are different ways, but the most common is through water.Hope this helps.

4 0

4 years ago

The student is now told that the four solids, in no particular order, are calcium bromide (CaBr2), sugar (C6H12O6), benzoic acid

nataly862011 [7]

<h2>Answer : The order of conductivity from most conductive to least is this - </h2><h2>Calcium bromide $(CaBr_{2})$ , Potsassium bromide (KBr), Benzoic acid $C_{6}H_{5}COOH$ and last is sugar.</h2><h3>Explanation : </h3>

When dissolved in water $(CaBr_{2})$ produces three ions namely; $Ca^{+2}$ and $2Br^{-}$ which acts as best conductor amongst the given choices.

Next is potassium bromide when dissolved in water generates only two ions which are $K^{+}$ and $Br^{-}$ and acts as an conductor.

Benzoic acid $C_{6}H_{5}COOH$ , is a weak acid and is slightly ionized so it acts as an weak conductor.

Sugar is a non ionized compound so it is anon conductor.

3 0

3 years ago

Read 2 more answers

How may a substance be tested to determine whether or not it is an element

yaroslaw [1]

Always remember that a compound can be separated into simpler substances by chemical methods/reactions. While elements cannot be broken down into simpler substances by chemical reactions. You can do a flame test and spectrum analysis to determine whether a solid material is an element or a compound. Check the boiling and/or melting point, color or density. Also check the solid material’s reaction with oxygen, hydrogen, calcium, or various acids. Examine and study its physical chemistry. The element(s) that may be present may be identified by checking the absorption edges from an x-ray spectrum.

7 0

3 years ago

7. Calculate the amount of energy required heat 100.g to the following: a. H2O(s) changes to H2O(l) at 0°C b. H2O(l) changes to

Delicious77 [7]

a=b=33400 J

c=4180 J

Further explanation

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

The heat of fusion for water at 0 °C : 334 J/g and the heat of vaporization at 100 °C : 2,230J/g

a. melting

$\tt Q=100.334=33400~J$

b. freezing

$\tt Q=100.334=33400~J$

c.raise the temperature(c water = 4.18 J/g C)

$\tt Q=100\times 4.18\times (20-10)=4180~J$

5 0

3 years ago

A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu

Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0

3 years ago