Answer:
Lead (II) iodide
Explanation:
The reaction of lead (II) nitrate, Pb(NO₃)₂ with KI is:
Pb(NO₃)₂(aq) + 2KI(aq) → KNO₃(aq) + PbI₂(s)
This is a typical double-replacement reaction where anions and cations exchange its couple.
All nitrates are solubles, thus, KNO₃ is not the precipitate.
The only possibility of precipitate is PbI₂,
Lead (II) iodide, a yellow and insoluble solid...
Answer:
The new concentration will be 0.01 M.
Explanation:
To determine the new concentration we use the following formula.
concentration (1) × volume (1) = concentration (2) × volume (2)
concentration (1) = 0.1 M
volume (1) = 100 mL
concentration (2) = unknown
volume (2) = 100 mL + 900 mL = 1000 mL
concentration (2) = [concentration (1) × volume (1)] / volume (2)
concentration (2) = (0.1 × 100) / 1000 = 0.01 M
Molecular Formula of Propanoic Acid is....
C₃H₆O₂Where;
Atomic Mass of C = 12
Atomic Mass of H = 1
Atomic Mass of O = 6
Substituting Atomic Masses in molecular formula,
(12)₃ + (1)₆ + (16)₂
36 + 6 + 32
74 g/mol
Result:
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,
I would say it would be a. It makes the most sense