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soldi70 [24.7K]
3 years ago
9

A small button placed on a horizontal rotating platform with diameter 0.320 m will revolve with the platform when it is brought

up to a speed of 40.0 rev min, provided the button is no more than 0.150 m from the axis. (a) What is the coefficient of static friction between the button and the platform
Physics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

0.2687 approximately 0.27

Explanation:

Diameter = 0.320

Speed = 40.0 rev/min

We are required to find coefficient of static friction between friction and button

The radius can be calculated as

0.320/2

= 0.160m

Then we have the rotational speed w = 40rev/min x 2pi/60

= 4.19 rad/s

umg = mrw²

u = mrw²/mg

u = rw²/g -------(1)

g = 9.8

When we put values into equation 1

0.150m x 4.19² / 9.8

= 0.150m x 17.5561 /9.8

= 0.2689

This is approximately 0.27

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11Alexandr11 [23.1K]

Answer:

a=g(sinθ-μkcosθ)

Explanation:

In an inclined plane the forces that interact with the object can be seen in the figure. The normal force, the weight w and the decomposition of the force vector of weight can be observed.

wx=m*g*sinθ

wy=m*g*cosθ

As the objects moves down an incline, acceleration in y axis is 0.

Then, by second Newton's Law:

Fy = m*ay

FN - m*g cos θ = 0,

FN=m*g cos θ

In x axis the forces that interacs are the x component of weight and friction force:

Fx = m*ax

mg sen u-FN*μk=m*a

Being friction force, Fr=FN*μk, we replace with its value in below formula:

m*g *sinθ-(m*g*cosθ*μk)=m*a

Then, isolating a:

a=(m*g sinθ-(m*g*cosθ*μk))/m

Solving, we have next equation:

a=g sinθ-(g*cosθ*μk)

Applying distributive property we have:

a=g*(sinθ-μk*cosθ)

5 0
3 years ago
Thanks + BRAINLIST <br><br> Need correct answer ASAP
aliina [53]

Answer:

The options are not shown, so it is kinda hard to give you the exact answer.

But i can try to give a general explanation on the topic.

Interference happens when two waves interact between them. We usually use waves with the same wavelength and same phase.

There are two "main" types of interference:

Destructive interference: Happens when the peak of one wave and the trough of the other wave happen in the same place, then when we add these waves, we have a subtraction, and then the amplitude of the resultant wave is smaller than the amplitudes of the original waves (if both initial waves have the same amplitude, then the amplitude of the resultant wave in that position is zero).

Constructive interference: Similar to the previous case, but now the two waves have the peaks or toughs in the same position, then when we add the waves, we have an addition in the amplitude, then the amplitude of the resultant wave will be larger than the amplitudes of the initial waves.

Then if you are looking for constructive interference, you need to look for an option where the peaks of the waves coincide. For example, in the top image we can see, at the top, a wave with an amplitude of 2 units.

And at the bottom a wave with an amplitude of 1 unit.

We also can see that the peaks (and the tough) are in the same place, then we will have constructive interference. Then the amplitude of the resultant wave will be equal to the sum of the amplitudes of the initial waves (2 and 1)

Then the amplitude of the resultant wave is 2 units + 1 unit = 3 units.

5 0
3 years ago
A car covers 120 km in 3 hours calculate its speed in m/s​
8_murik_8 [283]

Answer:

11.1 m/s

Explanation:

120 km = 120 x 1,000 = 120,000 m

3 hours = 3 x 60 x 60 = 3600 x 3 = 10,800 s

speed = 120,000 / 10,800

= 1200/108

= 11.1 m/s

6 0
2 years ago
Read 2 more answers
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zysi [14]

Answer:

W = 5/4 Mgℓ

Explanation:

Sum of forces:

∑F = ma

T − Mg = M (g/4)

T = 5/4 Mg

Work = force × distance

W = Tℓ

W = 5/4 Mgℓ

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3 years ago
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