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soldi70 [24.7K]
3 years ago
9

A small button placed on a horizontal rotating platform with diameter 0.320 m will revolve with the platform when it is brought

up to a speed of 40.0 rev min, provided the button is no more than 0.150 m from the axis. (a) What is the coefficient of static friction between the button and the platform
Physics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

0.2687 approximately 0.27

Explanation:

Diameter = 0.320

Speed = 40.0 rev/min

We are required to find coefficient of static friction between friction and button

The radius can be calculated as

0.320/2

= 0.160m

Then we have the rotational speed w = 40rev/min x 2pi/60

= 4.19 rad/s

umg = mrw²

u = mrw²/mg

u = rw²/g -------(1)

g = 9.8

When we put values into equation 1

0.150m x 4.19² / 9.8

= 0.150m x 17.5561 /9.8

= 0.2689

This is approximately 0.27

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Answer:

repel each other

Explanation:

The magnitude of the charge of an electron is called... ... If a positively-charged glass rod is suspended so that it turns easily and another positively-charged glass rod is brought close to it, the two rods will... Repel each other.

8 0
3 years ago
A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?
Galina-37 [17]

Answer:

<h2>109.52 Hz</h2>

Explanation:

The frequency of the wave when given it's velocity and wavelength only can be found by using the formula

f =  \frac{c}{ \lambda}  \\

where

c is the velocity of the wave in m/s

\lambda is the wavelength in meters

From the question we have

c = 230 m/s

\lambda = 2.1 m

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We have the final answer as

<h3>109.52 Hz</h3>

Hope this helps you

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3 years ago
A diet rich in high-density lipoproteins (HDLs) can help cleanse and open arteries that are clogged with plaque.
docker41 [41]

Correct answer choice is :


A) True


Explanation:


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3 years ago
Read 2 more answers
The primary __________ cortex specializes in receiving signals from different parts of the body.
tiny-mole [99]

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Explanation:

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3 years ago
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A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction, how fast
sladkih [1.3K]

Answer:

1.6s

Explanation:

Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,

To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.

Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh

Where h = 5.2sin25

h = 2.2 m

P.E = 1.2 × 9.8 × 2.2

P.E = 25.84 j

At the bottom, K.E = P.E

1/2mv^2 = 25.84

Substitutes mass into the formula

1.2 × V^2 = 51.69

V^2 = 51.69/1.2

V^2 = 43.07

V = 6.56 m/s

Using the third equation of motion

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Since the object started from rest,

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a = 43.07/10.4

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Where U = 0

6.56 = 4.14t

t = 6.56/4.14

t = 1.58s

Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s

6 0
3 years ago
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