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Leno4ka [110]
3 years ago
7

A competitive go-cart driver is traveling at a speed of 32m/s. He sees a caution flag go up and slows down at a rate of -1.5 m/s

squared in 10.8 seconds. What is his final velocity?
Physics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

His final velocity is 15.8 m/s.

Step-by-step explanation:

Given:

Initial velocity of the driver is, u=32 m/s

Acceleration of the driver is, a=-1.5 m/s²

Time taken to reach final velocity is, t=10.8 s.

The final velocity is given using the Newton's equations of motion as:

v=u+at, where, v is the final velocity.

Now, plug in the given values and solve for v.

v=32-1.5(10.8)\\v=32-16.2=15.8\textrm{ m/s}

Therefore, his final velocity is 15.8 m/s.

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Gases tend to deviate from the ideal gas law at
IgorLugansk [536]
<h2>Answer: high pressures</h2>

The Ideal Gas equation is:

P.V=n.R.T  

Where:

P is the pressure of the gas

n the number of moles of gas

R=0.0821\frac{L.atm}{mol.K} is the gas constant

T is the absolute temperature of the gas in Kelvin.  

According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them.

Now, real gases can behave approximately to an ideal gas, under the conditions described above.

However, when <u>temperature is low</u> these gases deviate from the  ideal gas behavior, because the molecules move slowly, allowing the repulsion or attraction forces to take effect.

The same happens at <u>high pressures</u>, because the volume of molecules is no longer negligible.

5 0
4 years ago
Suppose an asteroid orbiting the sun had an orbital period of 7. 5 years. What would its orbital radius be?.
creativ13 [48]

By using the orbital period equation we will find that the orbital radius is r = 4.29*10^11 m

<h3>What is the orbital period?</h3>

This would be the time that a given body does a complete revolution in its orbit.

It can be written as:

T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }

Where:

  • π = 3.14
  • G is the gravitational constant = 6.67*10^(-11) m^3/(kg*s^2)
  • M is the mass of the sun = 1.989*10^30 kg
  • r is the radius, which we want to find.

Rewriting the equation for the radius we get:

T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\\\\r = \sqrt[3]{ \frac{T^2*G*M}{4*\pi ^2} }

Where T = 7.5 years = 7.5*(3.154*10^7 s) = 2.3655*10^8 s

Replacing the values in the equation we get:

r = \sqrt[3]{ \frac{(2.3655*10^8 s)^2*(6.67*10^{-11} m^3/(kg*s^2))*(1.989*10^{30} kg)}{4*3.14 ^2} } = 4.29*10^{11 }m

So the orbital radius is 4.29*10^11 m

If you want to learn more about orbits, you can read:

brainly.com/question/11996385

7 0
2 years ago
What is a creative name for an element? (like oxygen, phosphorus) try to make it good
Inga [223]
Oxyles i think this suite Oxyles what do you think.
4 0
3 years ago
What are the major process of water cycle
Cerrena [4.2K]

Answer:

the major process of water cycle are :

  • Evaporation
  • Condensation
  • Precipitation

hope it helps!

5 0
3 years ago
Read 2 more answers
If a person (weighs 70kg) jumped of a moving car (at 100km/h) and fell on asphalt what is the amount of force applyied to his bo
jok3333 [9.3K]

Answer:

The amount of force applied to his body is 1944.44 N

<em>The chances of the person dying is very high owing to the high impact force with which the person would experience when he or she lands on the asphalt road due to the jump out of the moving car.</em>

Explanation:

We all know that,

F = Ma where,

F = Force

M = weight of the person

a = acceleration or velocity of the moving car

Therefore;

F = { 70 x (100 x 1000) } / [3600]

= [7 000 000] / 3600

= <u>1944.44 N</u>

6 0
3 years ago
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