Answer: the ladder
Explanation: since the energized conductor is already in contact with the ladder there by making electric current to flow. The base of the ladder is on the ground there by making the circuit to be complete and causing electrocution.
Answer:

Explanation:
using the law of the conservation of energy:


where K is the spring constant, x is the spring compression, N is the normal force of the block,
is the coefficiet of kinetic friction and d is the distance.
Also, by laws of newton, N is calculated by:
N = mg
N = 3.35 kg * 9.81 m/s
N = 32.8635
So, Replacing values on the first equation, we get:

solving for
:

Answer:
ac = 3.92 m/s²
Explanation:
In this case the frictional force must balance the centripetal force for the car not to skid. Therefore,
Frictional Force = Centripetal Force
where,
Frictional Force = μ(Normal Force) = μ(weight) = μmg
Centripetal Force = (m)(ac)
Therefore,
μmg = (m)(ac)
ac = μg
where,
ac = magnitude of centripetal acceleration of car = ?
μ = coefficient of friction of tires (kinetic) = 0.4
g = 9.8 m/s²
Therefore,
ac = (0.4)(9.8 m/s²)
<u>ac = 3.92 m/s²</u>
The tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.
<h3>Principle of moments</h3>
The Principle of Moments states that when a body is in equip, the sum of clockwise moment about a point is equal to the sum of anticlockwise moment about the same point.
The formula for calculating moment is given below:
- Moment = Force × perpendicular distance from the pivot
<h3>Calculating the tension in the chains</h3>
From the principle of moments:
Let tension in chain 1 be T1 and tension in chain 2 be T2.
T1 + T2 = 150 + 650 + 419
T1 + T2 =1219
Taking all distances from chain 1,
Sum of Moments = 0
419 × 0.5 + 150 × 0.85 + 650 × 0.9 = T2 × 1.7
T2 = 922/17
T2 = 542.35 N
Then, T1 = 1219 - 542.35
T1 = 676.65 N
Therefore, the tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.
Learn more about tension and moments at: brainly.com/question/187404
brainly.com/question/14303536
Answer:
4515.49484 N
4329.10484 N
Explanation:
r = Radius of balloon = 4.4 m
m = Mass of balloon with instruments = 19 kg
g = Acceleration due to gravity = 9.81 m/s²
Volume of balloon

The Buoyant force = Weight of the air displaced

The buoyant force acting on the balloon is 4515.49484 N
Net force on the balloon

The net force on the balloon is given by 4329.10484 N
As the balloon goes up the pressure outside reduces as the density of air decreases while the air pressure inside the balloon is high hence, the radius of the balloon tend to increase as it rises to higher altitude.