All categories

3 years ago

Question 4 of 10

Physics

1 answer:

Alexus [3.1K]3 years ago

7 0

Answer:

22.3 kg•m/s

Explanation:

Apex;)

You might be interested in

What happens to the size of the static frictonal force as you begin to pull on the force scale

Veronika [31]

It is at its peak force, it takes the most force to overcome the static stare because of inertia

3 0

4 years ago

Read 2 more answers

At a certain distance from the center of the Earth, a 0.4-kg object has a weight of 2.0 N. (a) Find this distance. (b) If the ob

Alika [10]

Answer:

a) The distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object is 5 m/s².

Explanation:

a) The distance can be found using the equation of gravitational force:

$F = \frac{GMm}{r^{2}}$

Where:

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

M: is the Earth's mass = 5.97x10²⁴ kg

m: is the object's mass = 0.4 kg

F: is the force or the weight = 2.0 N

r: is the distance =?

The distance is:

$r = \sqrt{\frac{GMm}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.97 \cdot 10^{24} kg*0.4 kg}{2.0 N}} = 8.92 \cdot 10^{6} m$

Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object can be calculated knowing the weight:

$W = ma$

Where:

W: is the weight = 2 N

a: is the initial acceleration =?

$a = \frac{W}{m} = \frac{2 N}{0.4 kg} = 5 m/s^{2}$

Therefore, the initial acceleration of the object is 5 m/s².

I hope it helps you!

4 0

3 years ago

A crate weighing 1000 Newton's needs to be lifted at a constant speed from the ground to a loading dock 1.5 meters high in 5.0 s

miskamm [114]

Answer:

the Power required is 300 W

Explanation:

We know that the definition of work is given by the following expresion:

$W=F*d$

the distance is 1.5 meters and the Force is equal to 1000 N.

Replacing this values in the work expresion

$w= 1000 *1.5 = 1500 J$

And the power is equal to the amount of work done in a given time, therefore we have:

$Power = \frac{work}{time} \\$

Time in seconds

$Power = 1500/5\\\\Power = 300 watts$

3 0

3 years ago

Which of the following is the correct equation we get

UkoKoshka [18]

Answer:

$\frac{a}{b}=c$ which agrees with the third answer in your list of answer options

Explanation:

Start with:

$a=b\,*\,c$

divide both sides by b to isolate c on the right:

$\frac{a}{b} =\frac{b\,*\,c}{b} \\\frac{a}{b} =c$

6 0

3 years ago

When a train first starts going down the railroad, it is very difficult for it to get going. When it comes to a stop, it has a h

Sveta_85 [38]

A train is a very big and heavy object, so the bigger the object is, the slower it will begin to move. With that said, bigger objects are also heavier and will move fast once going. Since the train is a huge and heavy object it will need longer time to slow down and come to a stop.

4 0

3 years ago