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kumpel [21]
2 years ago
15

Calculate the standard entropy change for the following reaction cu(s) + 1/2 O2(g) —> cuo(s)

Chemistry
2 answers:
Evgen [1.6K]2 years ago
8 0

3433Explanation:

the awser sucks and its not RIGHT

IceJOKER [234]2 years ago
8 0

Answer:

The standard entropy change for the reaction -93.12 J/K.mol

Explanation:

The Standard entropy change:

\Delta S^{0} = \Sigma nS^{0}(products) - \Sigma mS^{0}(reactants)

ΔS° = [42.59] - [33.17 + (205.07/2)] J/K.mol

ΔS° = [42.59] - [33.17 + 102.535] J/K.mol

ΔS° = [42.59] - [135.705] J/K.mol

ΔS° = - 93.12 J/K.mol

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Marina CMI [18]

Answer:

option d

Explanation:

Molecular sizes of gaseous molecules are very less. Volume occupied by the all the molecules of the gases are very less or negligible as compared to the container in which it is kept. Therefore, most of the volume occupied by gaseous molecules are negligible.

Volume occupied by the gaseous molecules are actually the volume of the container and its does not depend upon the amount, molecular mass or dipole moment of the gaseous molecules.

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3 years ago
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ahrayia [7]
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7 0
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OverLord2011 [107]

Answer:

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Explanation:

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5 0
2 years ago
The standard unit for measuring mass is the gram.<br> a. True<br> b. False
Ann [662]
b. False is the correct answer.

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Hope this helps~
5 0
3 years ago
Read 2 more answers
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7 0
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