Question

Calculate the standard entropy change for the following reaction cu(s) + 1/2 O2(g) —> cuo(s)

Answer 1

3433Explanation:

the awser sucks and its not RIGHT

Answer 2

Answer:

The standard entropy change for the reaction -93.12 J/K.mol

Explanation:

The Standard entropy change:

$\Delta S^{0} = \Sigma nS^{0}(products) - \Sigma mS^{0}(reactants)$

ΔS° = [42.59] - [33.17 + (205.07/2)] J/K.mol

ΔS° = [42.59] - [33.17 + 102.535] J/K.mol

ΔS° = [42.59] - [135.705] J/K.mol

ΔS° = - 93.12 J/K.mol