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kumpel [21]
3 years ago
15

Calculate the standard entropy change for the following reaction cu(s) + 1/2 O2(g) —> cuo(s)

Chemistry
2 answers:
Evgen [1.6K]3 years ago
8 0

3433Explanation:

the awser sucks and its not RIGHT

IceJOKER [234]3 years ago
8 0

Answer:

The standard entropy change for the reaction -93.12 J/K.mol

Explanation:

The Standard entropy change:

\Delta S^{0} = \Sigma nS^{0}(products) - \Sigma mS^{0}(reactants)

ΔS° = [42.59] - [33.17 + (205.07/2)] J/K.mol

ΔS° = [42.59] - [33.17 + 102.535] J/K.mol

ΔS° = [42.59] - [135.705] J/K.mol

ΔS° = - 93.12 J/K.mol

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damaskus [11]
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3 0
3 years ago
What enables Dna to have so many variations with only 4 chemicals?
elena-s [515]
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5 0
3 years ago
How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he
Lena [83]

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

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3 years ago
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Answer:  im in 8th they got me doin this

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8 0
3 years ago
How many atoms are in 5.00 grams of aluminum foil.​
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