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Mila [183]
3 years ago
7

A boy 12.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the i

nstant the ball is thrown. If the boy throws the ball horizontally at 8.50 m/s, (a) how fast must the dog run to catch the ball just as it reaches the ground, and (b) how far from the tree will the dog catch the ball?
Physics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

Explanation:

Height covered = 12m

time to fall by 12 m

s = 1/2 gt²

12 = 1/2 g t²

t = 1.565 s

Horizontal distance of throw

= 8.5 x 1.565

= 13.3 m

This distance is to be covered by dog during the time ball falls ie 1.565 s

Speed of dog required = 13.3 / 1.565

= 8.5 m /s

b ) dog will catch the ball at a distance of 13.3 m .

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Aaron's normal response time to apply the car brakes is 0.7 seconds. Aaron's response time doubles when he is tired. How far wil
Likurg_2 [28]

Aaron's car is moving at speed of 30 m/s

His reaction time is given as 0.7 s

but when he is tired the reaction time is doubled

Now we need to find the distance covered by his car when he is tired during the time when he react to apply brakes

So here since during this time speed is given as constant so we can say that distance covered can be product of speed and time

So here we can use

d = v*t

d = 30 * 1.4

d = 42 m

So the car will move to 42 m during the time when he apply brakes

3 0
3 years ago
An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum
Tju [1.3M]

Answer:

The pressure is  P_2  =  4.25 \ a.t.m

Explanation:

From the question we are told that

   The initial pressure is P_1  =  11.2\ a.t.m

   The  temperature is  T_1 =   299 \ K

   

Let the first volume be  V_1 Then the final volume will be  2 V_1

 Generally for a diatomic  gas

           P_1 V_1 ^r  =  P_2  V_2  ^r

Here r is the radius of the molecules which is  mathematically represented as

    r =  \frac{C_p}{C_v}

Where C_p \  and\   C_v are the molar specific heat of a gas at constant pressure and  the molar specific heat of a gas at constant volume with values

     C_p=7 \  and\   C_v=5

=>   r =  \frac{7}{5}

=>  11.2*( V_1 ^{\frac{7}{5} } ) =  P_2  *  (2 V_1 ^{\frac{7}{5} } )

=>   P_2  =  [\frac{1}{2} ]^{\frac{7}{5} } * 11.2

=>  P_2  =  4.25 \ a.t.m

8 0
3 years ago
Name the processes of going (a) from a solid to a gas and (b) from a gas to a solid.
marissa [1.9K]
The answer to the first one is sublimation.
8 0
3 years ago
Define density<br><br> Please help!!
Romashka-Z-Leto [24]

, density is how compact an object is. Put another way, density is the mass of an object divided by its volume.

5 0
3 years ago
A student drops a rock from a bridge to the water 12.7 m below. with what speed does the rock strike the water? the acceleration
kolezko [41]

The rock strike the water with the speed of 15.78 m/sec.

The speed by which rock hit the water is calculated by the formula

v=\sqrt{2gh}

v=\sqrt{2*9.8*12.7}

v=15.78 m/sec

Hence, the rock strike the water with the speed of 15.78 m/sec.

7 0
3 years ago
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