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ira [324]
3 years ago
14

How would being lactose intolerant affect someone who has galactosemia? It would make the effects of galactosemia more severe, b

ecause more galactose would be metabolized. It would make the effects of galactosemia more severe, because more lactose would be metabolized. It would be protective, because less dietary lactose would be hydrolyzed into glucose and galactose. It would have no effect.
Chemistry
1 answer:
lakkis [162]3 years ago
4 0

Answer:

It would make the effects of galactosemia more severe, because more lactose would be metabolized.

Explanation:

Galactosemia is an autosomal recessive disorder. People with this order usually have no problem in the digestion of lactose or absorption of galactose.

People who are lactose intolerant must however avoid food with large amounts of lactose because they can’t digest or metabolize it though they are able to digest and metabolize galactose.

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sasho [114]
I would answer B!! But your guess is as good as mine!!
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3 years ago
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A K+ ion is similar to a Cl– ion in that they both have the same A) nuclear charge B) number of electrons C) atomic number D) nu
pshichka [43]

Answer:

B) number of electrons

Explanation:

The two species:

          K+   and Cl- have the same number of electrons.

A neutral atom of K has 19 electrons

A neutral atom of Cl has 17 electrons

Now,

 To form K+, K will have to lose an electron and then the number of electrons becomes 18

To form Cl-, Cl will have to gain an electrons and then the number of electrons becomes 18

So, therefore, the number of electrons on both species is 18

3 0
3 years ago
What’s the answer ?
Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

6 0
3 years ago
Which is not a characteristic of poloyatomic ions​
Amiraneli [1.4K]

Answer:

iconic bonded unit

polyatomic ions can be covalently bonded

it has cations and anions

3 0
3 years ago
Convert 1297 cm to m.
Svet_ta [14]

Answer:

Not sure,12.97(if u get it wrong let me know)

Explanation:

100cm=1m

Then 1297cm=

1297 \100

= 12.97m

3 0
3 years ago
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