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ELEN [110]
4 years ago
14

What does heat do to an elecron

Chemistry
2 answers:
ira [324]4 years ago
3 0

Answer:

Heat, light and electricity can all be used to move electrons between orbitals. The electrons are what allow atoms to react with each other in chemical reactions, and they are also what cause certain compounds to emit light when heated. When an atom is heated up, it starts to vibrate intensely. I hope this helped you. :)

Charra [1.4K]4 years ago
3 0

Answer:

electrons move between orbitals

Explanation:

one electron will enter the electron cloud of an atom, and another one will leave, continuing the flow of electrons through the conductor. When a solid is heated up, the atoms in it move around.

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Just need question 3 answered!!
Naddika [18.5K]

Answer:

C

Explanation:

There are 5 valence electrons

3 0
3 years ago
Read 2 more answers
What is the pOH of 0.50 molar H3BO3?
Crazy boy [7]

<u>Answer:</u>

<em>A. 10.25</em>

<em></em>

<u>Explanation:</u>

Pkb =4.77

So pka = 14 - pka = 9.23

Ka =10^{-pka}

H_3 BO_3 (aq)+ H_2 O(l) H_2 BO_3^- (aq)+H_3 O^+ (aq)

Initial                0.50M                                 0                                 0

Change                  -x                                 +x                               +x

Equilibrium    0.50M-x                               +x                               +x

Ka =\frac {((x)(x))}{(0.50M-x)}

5.88\times10^{-10}= \frac {x^2}{(0.50M-x)}

(-x is neglected) so we get

5.88\times10^{-10}\times0.50=x^2\\\\x^2=2.94\times10^{-10}

x=\sqrt{x^2}=1.72\times10^{-5} M=H^3 O^{+}

pH=-log[H^3 O^+]\\\\pH=-log[1.72\times10^{-5}]\\\\pH=4.76

pOH = 14 - pH

= 14 - 4.76

pOH = 9.24 is the answer

Option A - 10.25 is the answer which is close to 9.24

4 0
3 years ago
What is the common name of the following compound
Masja [62]
Hey there!

Here is your answer:

<u><em>The proper answer to this question is option D "sec-butyl bromide".</em></u>

Reason:

<u><em>S</em></u><span><u><em>ec-butyl bromide looks often like this:</em></u>

<em>Therefore the answer is option D!</em>

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
</span>

4 0
3 years ago
Read 2 more answers
Describe how spead, velocity and<br> brcoloration are related.
Flura [38]

Answer:

Speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance (a scalar quantity) per time ratio. On the other hand, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes.

3 0
4 years ago
Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or
Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

  • The oxidation number of a free element is always zero.
  • The oxidation number of a monatomic ion equals the charge of the ion.
  • The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.
  • The oxidation number of  oxygen (O)  in compounds is usually -2.
  • The oxidation number of a Group 17 element in a binary compound is -1.
  • The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
  • The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) H_2SO_4

Let the oxidation state of 'S' be, 'x'

2(+1)+x+4(-2)=0\\\\x=+6

Hence, the oxidation state of 'S' is, (+6)

(b) Ca(OH)_2

Let the oxidation state of 'Ca' be, 'x'

x+2(-2+1)=0\\\\x=+2

Hence, the oxidation state of 'Ca' is, (+2)

(c) BrOH

Let the oxidation state of 'Br' be, 'x'

x+(-2)+1=0\\\\x=+1

Hence, the oxidation state of 'Br' is, (+1)

(d) ClNO_2

Let the oxidation state of 'N' be, 'x'

-1+x+2(-2)=0\\\\x=+5

Hence, the oxidation state of 'N' is, (+5)

(e) TiCl_4

Let the oxidation state of 'Ti' be, 'x'

x+4(-1)=0\\\\x=+4

Hence, the oxidation state of 'Ti' is, (+4)

(f) NaH

Let the oxidation state of 'Na' be, 'x'

x+(-1)=0\\\\x=+1

Hence, the oxidation state of 'Na' is, (+1)

4 0
3 years ago
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