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2 years ago

What type of compound results from the reaction of an acid chloride and a 2° amine?

Chemistry

1 answer:

Butoxors [25]2 years ago

8 0

Amide is produced when a 2° amine and an acid chloride combine.

Acid chloride: What is it?

The chemical name for acid chloride is RCOCl, where "R" stands for a side chain. They are reactive derivatives of carboxylic acids. In organic chemistry, an acyl group and a chlorine atom form an organic molecule known as an acyl chloride (also known as acid chloride).
A functional group identified by the RCO molecular formula is called an acyl group. Since acyl chlorides are often hazardous, handling them requires extra care.
They have the potential to produce HCl and organic compounds when they interact with water on the surface of the eye, irritating the eye. Anhydrous acid salts are neutral because it lacks an H+ donor.

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Two substances with empirical formula HNO are hyponitrous acid (M = 62.04 g/mol) and nitroxyl (M = 31.02 g/mol).(a) What is the

viva [34]

The molecular formula for hyponitrous acid is H2N2O2. and for nitroxyl is HNO.

The chemical compound HNO is also known as nitroxyl (common name) or Azanon (IUPAC name). In the gas phase, it is widely recognized. In the solution phase, the short-lived intermediate nitroxyl can develop. Nitric oxide (NO) is reduced to form the conjugate base, NO, which is isoelectronic with dioxygen.

By oxidizing hydroxylamine with CuO , HgO, and Ag 2 and by oxidizing hydroxylamine with N2O3 in methyl-alcoholic solution, we can create hyponitrous acid.

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4 0

1 year ago

After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid

nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

$MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\$

Then, we add the half reactions:

$2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0$

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0

3 years ago

Which term correctly describes all of the following materials ? Salt water,vinegar , bronze,air,beach sand?

maksim [4K]

Answer:

ummmm hey

Explanation:

du sus su du du su du

7 0

3 years ago

Read 2 more answers

which of the following would represent an addition to a nation’s gdp a) ms. jone purchases a share of stock in a technology star

Elodia [21]

c) the government hires workers to install street lights

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6 0

3 years ago

2Al + 3CuSO4–>3Cu+ Al2(SO4)3

sergiy2304 [10]

Answer:

7.82 g of Cu

Explanation:

2 moles of Al react to 3 moles of copper sulfate in order to produce 3 moles of copper and 1 mol of aluminum sulfate.

Firstly we determine the moles of reactant.

As copper sulfate is in excess, Al is the limiting.

2.75 g . 1mol /26.98g = 0.102 moles

Ratio is 2:3. 2 moles of Al, can produce 3 moles of Cu

So the 0.102 moles of Al will produce(0.102 . 3) /2 = 0.153 moles.

We convert moles to mass: 0.153 mol . 63.5g /mol = 9.71 g

That's the theoretical yield (100 % yield reaction)

We know that: (yield produced / theoretical yield) . 100 = percent yield

We replace:

(Yield produced / 9.71g) . 100 = 80.5 %

(Yield produced / 9.71g) = 0.805

Yield produced = 0.805 . 9.71g = 7.82 g

4 0

3 years ago