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Andrej [43]
3 years ago
13

You stand at location A, a distance d from the origin, and hold a small charged ball. You find that the electric force on the ba

ll is 0.056 N. You move to location B, a distance 2d from the origin, and find the electric force on the ball to be 0.028 N. What object located at the origin might be the source of the field? (Select all that apply.)(a) a point charge(b) a dipole(c) a uniformly charged rod (for d ≪ L)(d) a uniformly charged ring (for d ≪ R)(e) a uniformly charged disk (for d ≪ R)(f) a uniformly charged hollow sphere(g) none of the above
Physics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

a uniformly charged rod (for d ≪ L)

Explanation:

Given:

- Force at point d is F_ 1= 0.056

- Force at point 2d is F_ 1= 0.028

Find:

 What object located at the origin might be the source of the field?

Solution:

- We see that as the distance is doubled that force is half. So we are looking at an object whose electric Field strength is inversely proportional to the distance from the source.

- A point charge, dipole, and hollow sphere all are related by distance being inversely proportional to squared of the distance.

- A charged ring with R >> distance will give us E = 0.

- A charged disc with R >> distance will act like a uniform infinite sheet of charge which in dependent of distance.

- A uniformly charged infinite rod is Electric field is proportional to inverse of distance from the charge. We can see that from a application of Gauss Law.  

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A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person  standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

7 0
3 years ago
What are the unit for acceleration
Flura [38]
<h3>Answer</h3>

m/s^2 (meter per sec square)

Explanation:

acc = change in velocity/time

= distance/time

----------------

time

= m/s

------

s

=m/s^2

7 0
3 years ago
A standing wave on a string that is fixed at both ends has frequency 80.0 Hz. The distance between adjacent antinodes of the sta
OlgaM077 [116]

Answer:

v = 19.2 m/s

Explanation:

In order to find the speed of the string you use the following formula:

f=\frac{v}{2L}          (1)

f: frequency of the string = 80.0Hz

v: speed of the wave = ?

L: length of the string = 12.0cm = 0.12m

The length of the string coincides with the wavelength of the wave for the fundamental mode.

Then, you solve for v in the equation (1), and replace the values of the other parameters:

v=2Lf=2(0.12m)(80.0Hz)=19.2\frac{m}{s}

The speed of the wave is 19.2 m/s

8 0
4 years ago
When the cylinder is displaced slightly along its vertical axis it will oscillate about its equilibrium position with a frequenc
Nesterboy [21]

Answer:

w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

Explanation:

We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is

          w² = mg d / I

In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow

         d = L / 2

The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated

        I = ¼ m r2 + ⅓ m L2

        I = m (¼ r2 + ⅓ L2)

now let's use the concept of density to calculate the mass of the system

        ρ = m / V

        m = ρ V

the volume of a cylinder is

         V = π r² L

          m =  ρ π r² L

let's substitute

        w² = m g (L / 2) / m (¼ r² + ⅓ L²)

        w² = g L / (½ r² + 2/3 L²)

        L >> r

         w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

4 0
4 years ago
A net force of 25N causes an object to accelerate at 4m/s^2. what is the mass of the object?
Doss [256]

Answer:

6.25 kg

Explanation:

Fnet=ma

m=Fnet/a

m=25/4

m=6.25kg

3 0
3 years ago
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