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azamat
3 years ago
6

Write the symbol for each of the following ions:

Chemistry
1 answer:
kap26 [50]3 years ago
3 0

Answer:

a) _{31}^{71}\textrm {P^{3+}}

b) _{35}^{80}\textrm {Br^{-}}

c) _{90}^{232}\textrm {Th^{4+}}

d) _{38}^{87}\textrm {Sr^{2+}}

Explanation:

For neutral atoms:

Atomic Number (Z)= number of protons = number of electrons

Mass number (A) = number of protons + number of neutrons

For ions with positive net charge:

Number of protons = Z + net charge

For ions with negative net charge:

Number of protons= Z - net charge

a) A = 71, Charge = +3

Number of electrons = 28

Number of protons = 28 +3 =31

_{31}^{71}\textrm {P^{3+}}

b)  A = 35, Z = 45+35=80, Charge = -1

Number of protons =35

Number of neutrons = 45

Number of electrons = 36

Charge = Number of protons- Number of electrons =35-36 = -1

_{35}^{80}\textrm {Br^{-}}

c)  Charge = +4

Number of electrons = 86

Number of protons = Z = 86+4 = 90

mass number = A = 90+142 = 232

_{90}^{232}\textrm {Th^{4+}}

d)  Charge = +2

Atomic number = Number of protons = Z = 38

mass number = A = 87

_{38}^{87}\textrm {Sr^{2+}}

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PLEASE ANSWER ASAP AND SHOW WORK: A camping stove uses a 5.0 L propane tank that holds 68.0 moles of liquid C3H8. How large a co
seropon [69]

<u>Answer:</u> The volume of the container needed is 554.6 L

<u>Explanation:</u>

To calculate the volume of the gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 3.0 atm

V = Volume of the gas = ? L

T = Temperature of the gas = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles of propane gas = 68.0 moles

Putting values in above equation, we get:

3.0atm\times ?L=68mol\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\V=\frac{68\times 0.0821\times 298}{3.0}=554.6L

Hence, the volume of the container needed is 554.6 L

6 0
3 years ago
Name two different signs of a chemical reaction
olasank [31]
A change in temperature or color are two signs that a chemical reaction has taken place.
7 0
4 years ago
Read 2 more answers
What is the pressure of a fixed volume of hydrogen gas at 38.8°C if it has a pressure of 1.36 atm at 15.0°C?
Rainbow [258]
Hello There! ^_^

Your question: What is the pressure of a fixed volume of hydrogen gas at 38.8°C if it has a pressure of 1.36 atm at 15.0°C..?

Your answer: P1/ T1= P2/ T2
                    
                     Change C to Kelvin
   
                     273+ C= K
               
                     38.3+ 273= 311K
                      
                      15.0+ 273= 288K
                       
                       2.38/ 288= P2/ 311.3
                          
                        740.894= 288 (P2)
                        
                         P2= 2.57 atm.


 Thus, you got you answer!

  Hope this helps!





  

       



    

 

  






4 0
3 years ago
How many grams of AlCl3 can be prepared from 3.5 moles of HCl gas?
poizon [28]

Answer:

156 g of AlCl₃ will be produced from 3.5 moles of HCl.

Explanation:

Given data:

Number of moles of HCl = 3.5 mol

Grams of AlCl₃ produced = ?

Solution:

Balanced Chemical equation:

3HCl + Al(OH)₃   →  AlCl₃ + 3H₂O

Now we will compare the moles of AlCl₃  with HCl from balanced chemical equation.

                   HCl          :           AlCl₃

                     3            :              1

                   3.5           :           1/3×3.5 = 1.17 mol

Mass of  AlCl₃ produced:

Mass = number of moles ×molar mass

Mass = 1.17 mol ×   133.341 g/mol

Mass =  156 g

Thus 156 g of AlCl₃ will be produced from 3.5 moles of HCl.

4 0
3 years ago
rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3, in order o
SVEN [57.7K]

Answer: H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)


Initial important note:


Although NaHCO₃ contents oxygen atoms, and you can calculate its compositoin, the resulting gas does not containg pure oxygen gas (O₂). For the comparisson it is not useful to calculate the content of oxygent atoms, but the concentration of O₂ gas. As such, the gas from NaHCO₃ contains 0% of pure O₂, that is why it is ranked last.


1) Air:


Source: internet


Approximate 23%. It is variable, because air is not a pure substance but a mixture of gases, whose compositon is not unique.


2) Exhaled air:


Source: internet.


Approximate 13%. The compositon of the air changes in our lungs, due to the respiration process: we inhale fresh air with around 23% of oxygen, part of this oxygen pass to the cells (lungs - blood - heart - cells) and then it is exhaled with a lower content of air and a greater content of CO₂


3) Air from the decomposition of H₂O₂.


In this case we can do a chemical calculation, since we can state the chemical equation of the reaction:


i) Chemical Equation:


H₂O₂ (g) → H₂ (g) + O₂ (g)


ii) mole ratio of the products 1 mol H₂ : 1 mol O₂


iii) convert moles into mass (grams)


1 mol H₂ × 2 × 1.008 g/mol = 2.016 g


1 mol O₂ × 2 × 15.999 g/mol = 31.998 g


Composition, % = [31.998 g / (2.016 g + 31.998 g) ] × 100 ≈ 94%



4) Air from the decomposition of NaHCO₃:


i) chemical equation:


2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)


ii) mole ratio: take into account only the gases in the products:


1 mol CO₂ (g) : 1 mol H₂O


iii) mass in grams


CO₂: molar mass ia approximately 44.01 g/mol


H₂O: molar mass is approximately 18.02 g/mol


iii) Those gases although have oxygen atoms, do not hae free oxygen gas, which is what we are compariing. That means, that from the decomposition of NaHCO₃ you get 0% oxygen gas.


5) The result is:


H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)

7 0
3 years ago
Read 2 more answers
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