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2 years ago

How many hours is 8 to 3 o'clock

Mathematics

2 answers:

julsineya [31]2 years ago

6 0

There will be 7 hours

sammy [17]2 years ago

4 0

8 to 12 is 4 hours and 12 to 3 is 3 hours. So the total hours is 7 hours

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Please help look at the picture

k0ka [10]

Answer:

y = - 5x - 1

Step-by-step explanation:

The first thing to do (always) is pay attention to x =0. That at least gives you a partial answer. y = y' - 1. when you put 0 in for whatever y' is you get 0. What about the other numbers? How did they come about.

We have another clue. Whenever you put in a positive number for x, you get a negative answer for y. That's interesting. So y' has a minus sign associated with it.

y = -ax - 1 Make a>0 so there is only 1 minus sign. x cannot have an even power, because an even power would make everything positive except the -1.

So we'll start with y= - ax - 1 We'll also make the assumption that a = 1

y = - x - 1 That won't work. a >1 otherwise x = 2 won't give - 11

y = -ax - 1

let x = 2

let y = - 11 Solve for a

y = - ax - 1

- 11 = -a*-2 - 1 add 1 to both sides

-11 + 1 = - a(-2) - 1 + 1

- 10 = -2a Divide by - 2

- 10/-2 = -2a/-2

a = 5

Answer: y = - 5x - 1

8 0

2 years ago

Which of the following fractions will convert to terminating decimals?

valina [46]

Answer:

B and D

Step-by-step explanation:

A terminating decimal differs from a repeating decimal in that ; terminating decimals have a finite number of numbers after a decimal point whereby repeating decimals Don not have a fine number of numbers after the decimal point.

Given :

A. 2/7 = 0.2857...

B. 3/2 = 1.5

C. 2/3 = 0.6666...

D. 3/5 = 0.6

E. 5/9 = 0.5555...

B and D are terminating decimal values.

6 0

2 years ago

A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall

Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is $\frac{1}{5}$

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

$\text{Probability}=\frac{5}{25}$

$\text{Probability}=\frac{1}{5}$

5 0

3 years ago

All the numbers round to 7 except 6.61 7.89 6.58 7.37

alisha [4.7K]

7.89 rounds off to 8

6 0

1 year ago

Read 2 more answers

Will give brainliest please help ASAP

Aleksandr [31]

Answer:

x-coordinate is 3; ordered pair in Quadrant 1;

Step-by-step explanation:

8 0

3 years ago