Answer:
The answer is option D.
Explanation:
An EMF device is a device that produces an electromagnetic field and the components that it has also have their own internal resistance.
This is the case in a real life EMF device but for an ideal EMF device, the internal resistance is equal to zero so there is no voltage drop because of that.
The answer is option D.
I hope this answer helps.
Answer:
t = 180 / 1.4 = 129 sec (time to swim horizontally across river)
S = 129 sec * V where V is speed of current and S is the distance he will be carried downstream
The problem does not specify V the speed of the river
Answer:
the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector
Explanation:
Given that:
The area vector of a square loop has 5 numbers of turns i.e n = 5
each with side length = 0.2 m
Current I = 2 A
uniform magnetic field = 50.0 T
Now; the magnitude of the total magnetic field B is calculated as :
B = IA
where;
I = current
A = area ( n × l²)
B = I ( n × l²)
B = 2 × 5 × 0.2²
B = 0.4 Am²
The direction of the magnetic moment is antiparallel to the area vector;
Hence ; the magnitude and the direction of the total magnetic field is 0.4 Am² antiparallel to the area vector
Initial speed of the train = 7 m/s
Final speed of the train = 17 m/s
Change of speed of the train = (17 - 7) m/s
= 10 m/s
Time taken for the change of the speed of the train = 120 s
Then
Acceleration of the train = Change of speed of the train/Time taken for the change of speed
= 10/120 m/s^2
= 1/12 m/s^2
= 0.083 m/s^2
So the acceleration of the train is 1/12 meter per second square or 0.083 m/s^2. I hope this is the answer you were looking for.
Answer:
475 m , 950 m
Explanation:
Let l be the length of the side perpendicular to the barn.
1900-2l = length of the side parallel to the barn
Area A= l( 1900-2l)
A= 1900l-2l^2
now, the maximum value of l ( the equation being quadratic)
l_max= -b/2a
a= 2
b=1900
l_max= -1900/4= 475 m
then 1900-2l= 1900-2×(475) = 950 m
So, the dimensions that maximize area are
950 and 475
Now. A_max = -2( l_max)^2+1900×l_max
A_max= -2(475)^2+1900×475
A_max= 451250 m^2
or, 475×950 = 451250 m^2
