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3 years ago

Can someone please solve these 6 questions and explain briefly? I really do not understand them. Thank you

Physics

1 answer:

Verizon [17]3 years ago

5 0

Explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

For example, in 2(a), we are given an angle and the hypotenuse. We want to find the side adjacent to the angle. Therefore, we should use cosine.

cos 58° = y / 32.3

y = 32.3 cos 58°

y ≈ 17.1

In 3(a), we are given the adjacent side and opposite side. We want to find the angle. So use tangent.

tan θ = 3.6 / 6.2

θ = tan⁻¹(3.6/6.2)

θ = 30.1°

In 4(a), we are given an angle and the hypotenuse. We want to find the side opposite of the angle. Therefore, we should use sine.

sin 47° = x / 29

x = 29 sin 47°

x ≈ 21.2

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You use 8x binoculars were used on a warbler (14cm long) in a tree 18cm away. What angle (in degrees) does the image of the warb

mafiozo [28]

Answer:

The angle it subtend on the retina is $\theta_z = 0.44586^o$

Explanation:

From the question we are told that

The length of the warbler is $L = 14cm = \frac{14}{100} = 0.14m$

The distance from the binoculars is $d = 18cm = \frac{18}{100} = 0.18m$

The magnification of the binoculars is $M =8$

Without the 8 X binoculars the angle made with the angular size of the object is mathematically represented as

$\theta = \frac{L}{d}$

$\theta = \frac{0.14}{0.18}$

$= 0.007778 rad$

Now magnification can be represented mathematically as

$M = \frac{\theta _z}{\theta}$

Where $\theta_z$ is the angle the image of the warbler subtend on your retina when the binoculars i.e the binoculars zoom.

$\theta_z = M * \theta$

=> $\theta_z =8 * 0.007778$

$= 0.0622222224$

Generally the conversion to degrees can be mathematically evaluated as

$\theta_z = 0.062222224 * (\frac{360 }{2 \pi rad} )$

$\theta_z = 0.44586^o$

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