B. The moon is located between the Sun and Earth
Answer:
13.2m
Explanation:
Step one:
given data
Energy= 5610J
Force F= 425N
Required
The distance traveled
Step two:
We know that work done is given as
WD= force* distance
so
5610=425*d
divide both sides by 425
d= 5610/425
d=13.2m
Answer:
Animal 1 because it takes 3s to go 25 meters 3.5s to go 50 meters and 5s to go 75 meters while the others take longer.
Explanation:
Answer:
Explanation:
Using the atomic mass of pluonium atoms (244 g/mol), you can calculate the number of atoms in 47.0 g. Then, knowing that each plutonium atom has 96 protons, you calculate the number of protons in the 47.0 g sample. Finally, using the positive charge of one proton, you calculate the total positive charge in the 47.0 g of plutonium.
<u>1. Number of atoms of plutonium in 47.0 g</u>
- Number of moles = mass / atomic mass = 47.0 g / 244 = 0.1926 moles
- Number of atoms = number of moles × 6.022 × 10²³ atoms/mol
- Number of atoms = 0.1926 mol × 6.022 × 10²³ atoms/mol = 1.15998×10²³ atoms
<u>2. Number of protons</u>
- Number of protons = 1.15998×10²³ atoms × 96 protons/atom = 1.11385×10²⁵ protons
<u>3. Charge</u>
<u />
- Charge = charge of one proton × number of protons
- Charge = 1.602×10⁻¹⁹ C/proton × 1.11385×10²⁵ protons = 1.78×10⁶C
Answer:
<em>The velocity after the collision is 2.82 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of the individual momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
If both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.
After the collision, both cars stick together. Let's compute the common speed after that:
The velocity after the collision is 2.82 m/s
