Change in velocity per time
7200 joules of heat and light energy was dissipated into the air. But no work was done ... no force moved through no distance.
Answer:
a)= 0.025602u
b) = 23.848MeV
c) N = 1.546 × 10¹³
Explanation:
The reaction is
²₁H + ²₁H ⇄ ⁴₂H + Q
a) The mass difference is
Δm = 2m(²₁H) - m (⁴₂H)
= 2(2.014102u) - 4.002602u
= 0.025602u
b) Use the Einstein mass energy relation ship
The enegy release is the mass difference times 931.5MeV/U
E = (0.025602) (931.5)
= 23.848MeV
c)
the number of reaction need per seconds is
N = Q/E
= 59W/ 23.848MeV
![= \frac{59}{(23.848 \times 10^6 )(1.6 \times 10^1^9) } \\\\= 1.546 \times 10^1^3](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B59%7D%7B%2823.848%20%5Ctimes%2010%5E6%20%29%281.6%20%5Ctimes%2010%5E1%5E9%29%20%7D%20%5C%5C%5C%5C%3D%201.546%20%5Ctimes%2010%5E1%5E3)
N = 1.546 × 10¹³
The formula for energy of motion is KE = .5 x m x v^2
Ke= Kinetic Energy in Joules
m = Mass in Kilograms
v = Velocity in Meters per Second
As v becomes zero at the highest point, i prefer considering different travelling directions so it will become less complicated.
dont forget to add the total time up .
also to master the skills, write down the "uvsat" may help (thats the way i found it easier to handle problems)