Answer:
I pretty sure the answer is Nervous
Hello :
<span>g(x) = 5x² - 50x + 128
= 5(x²-10x +128/5)
= 5 (x²-10x+5²-5² +128/5)
= 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
<u> 12x³ - 12x </u><u /> = 3/7 - 1/56x² - 3/7 = 3/7 - 3/7 - 1/56x² = -1/56x²
28x³ - 56x² + 28x
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they have to have the same slope.
y = 6x + 6 The slope of this line is 6, so the parallel line's slope is also 6.
Now that you know m = 6, substitute/plug it into the equation:
y = mx + b Plug in 6 for "m" in the equation
y = 6x + b To find "b", plug in the point (20, 1) into the equation
1 = 6(20) + b
1 = 120 + b Subtract 120 on both sides to get "b" by itself
1 - 120 = 120 - 120 + b
-119 = b Now that you know b = -119, plug it into the equation
y = 6x - 119
Answer:
Step-by-step explanation:
b^2 - 4ac > 0
(-8)^2 - 4(1)(-2) = 64 + 8 = 72
two solutions
