The ball is accelerating
Explanation:
On a distance-time graph, the slope of the graph represents the speed of the object represented.
Let's therefore calculate the slope (so, the speed of the ball) in the two intervals given.
In the first second, we have:
So the average speed is
In the next second, we have:
So the average speed is
We notice that the speed of the ball has increased from 20 m/s in the first second to 40 m/s in the next second: this means that the speed of the ball is increasing, and therefore, the ball is accelerating.
Learn more about acceleration:
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Answer:
The ball travels a distance of 20 m in the time interval of 4 s
Explanation:
Using s = ut + 1/2at² where s = distance travelled by the ball, u = initial velocity of ball = 0 m/s (since it starts from rest), a = acceleration of the ball = 2.50 m/s² and t = time = 4 s.
Substituting the variables into the equation, we have
s = ut + 1/2at²
s = 0 × 4 s + 1/2 × 2.50 m/s² × (4 s)²
s = 0 + 1/2 × 2.50 m/s² × 16 s²
s = 1/2 × 40 m
s = 20 m
So, the ball travels a distance of 20 m in the time interval of 4 s.
Answer:
neutral
Explanation:
3p - 3e = 0 and that leaves 2 neutrons so it will be neutral
Dimensional Formula of Density
The dimensional formula of density is given by,
[M1 L-3 T0]
Where,
M = Mass
L = Length
T = Time
Derivation
Density (ρ) = Mass × Volume-1 . . . . . (1)
The dimensional formula of volume = [M0 L3 T0] . . . . (2)
And, the dimensional formula of mass = [M1 L0 T0] . . . . (3)
On substituting equation (2) and (3) in equation (1) we get,
Density = Mass × Volume-1
Or, (ρ) = [M1 L0 T0] × [M0 L3 T0]-1 = [M1 L-3 T0]
Therefore, density is dimensionally represented as [M1 L-3 T0].
Hope i helped!
