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katrin [286]
3 years ago
15

How is the motion of an object affected when a force acts on it?

Physics
1 answer:
Arada [10]3 years ago
3 0

Newton's first law of motion is sometimes called the law of inertia. When the forces acting on an object are balanced, the object is either at rest or moving with a constant velocity. Unbalanced forces can cause an object to accelerate or decelerate. Unbalanced forces can also cause an object to change direction.

Hope that helps!

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Which of the following correctly describes the relationship between speed and velocity?
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If there is gravity where the International Space Station (ISS) is located above Earth, why doesn’t the space station get pulled
nasty-shy [4]

Answer:

Yes. Gravity is 90% of what it is on the earth's surface. ISS moves at such high speeds that the curve of its fall will always match  the curve of the earth and so will never hit the earth.

Explanation:

The location of the International Space Station (ISS) is at an altitude of about 200 or 250 miles above the earth's surface. Since gravity decreases with altitude, it is less at that height. Gravity is still present there. Since the ISS is in orbit around the earth, the condition is of free fall. Result of this free fall is apparent weightlessness. The high speed of the ISS allows it to orbit around in such a way that the gravitational pull of the earth is equal to the centripetal force experienced by the ISS in its orbit.

The conditions which make it remain in space are similar to how the moon stays in the orbit around the earth. Moon is also in free fall but it never falls down to earth.

7 0
3 years ago
A man weighing 700 NN and a woman weighing 440 NN have the same momentum. What is the ratio of the man's kinetic energy KmKmK_m
Eduardwww [97]

Answer:

The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

Explanation:

Given;

weight of the man, W = 700 N

Weight of the woman, W = 440 N

momentum is given by;

P = mv\\\\v = \frac{P}{m}

Kinetic energy of the man;

K_m = \frac{1}{2}m_m(\frac{P_m}{m_m})^2  \\\\K_m = \frac{P_m^2}{2m_m}

Momentum of the man is calculated as;

P_m^2 = 2m_mK_m

The kinetic energy of the woman is given by;

K_w = \frac{P_w^2}{2m_w}

The momentum of the woman is given;

P_w^2 = 2m_wK_w

Since, momentum of the man = momentum of the woman

P_m^2 = P_w^2

2m_mK_m = 2m_wK_w\\\\\frac{K_m}{K_w} = \frac{2m_w}{2m_m}\\\\\frac{K_m}{K_w} = \frac{m_w}{m_m}

mass of the mas = 700 / 9.8 = 71.429

mass of the woman is = 440 / 9.8 = 44.898

\frac{K_m}{K_w} = \frac{44.898}{71.429}\\\\\frac{K_m}{K_w} =0.629

Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

3 0
2 years ago
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