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qaws [65]
3 years ago
12

A 121 turn 121 turn circular coil of radius 2.85 cm 2.85 cm is immersed in a uniform magnetic field that is perpendicular to the

plane of the coil. Over an interval of 0.179 s 0.179 as, the magnetic field strength increases from 55.1 mT 55.1 mT to 97.9 mT 97.9 mT. Find the magnitude of the average emf E avg Avg induced in the coil during this time interval, in millivolts.
Physics
2 answers:
Alex Ar [27]3 years ago
8 0

Answer:

The magnitude of the average EMF = 73.83 mv

Explanation:

From faradays law of induction, EMF is given as;

EMF = NA(ΔB/Δt)

We are given that;

N = 121 turns

B1 = 55.1 mT

B2 = 97.9 mT

Thus, ΔB = 97.9 mT - 55.1 mT = 42.8 mT

t = 0.179 s

r = 2.85cm = 0.0285 m

Area = πr² = π x (0.0285)² = 0.0025518 m²

Plugging in the relevant values, we can calculate EMF as;

EMF = (121)(0.0025518)(42.8 mT/0.179) = 73.83 mv

sashaice [31]3 years ago
5 0

Answer:

0.074 V

Explanation:

Parameters given:

Number of turns, N = 121

Radius of coil, r = 2.85 cm = 0.0285 m

Time interval, dt = 0.179 s

Initial magnetic field strength, Bin = 55.1 mT = 0.0551 T

Final magnetic field strength, Bfin = 97.9 mT = 0.0979 T

Change in magnetic field strength,

dB = Bfin - Bin

= 0.0979 - 0.0551

dB = 0.0428 T

The magnitude of the average induced EMF in the coil is given as:

|Eavg| = |-N * A * dB/dt|

Where A is the area of the coil = pi * r² = 3.142 * 0.0285² = 0.00255 m²

Therefore:

|Eavg| = |-121 * 0.00255 * (0.0428/0.179)|

|Eavg| = |-0.074| V

|Eavg| = 0.074 V

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Answer:

10500 J/kg/*C

Explanation:

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Quantity of heat required=0.25 x 4200 x [30-20]

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Quantity of heat required=10500 J/kg/*C

3 0
3 years ago
A museum sets up a display of fluorescent minerals. which best describes how electromagnetic waves can be used to enhance the di
IRISSAK [1]

Answer:

ultraviolet light shining on the minerals will cause them to give off visible light.

Explanation:

Here we know that in all electromagnetic waves have certain range of energy

Here in the above case when a given frequency range of electromagnetic wave incident on the fluorescent mineral then that mineral will absorb few amount of energy and the remaining energy will throw back into the surrounding again.

So here the main concept is that when a electromagnetic wave which is higher in energy then visible light incident on fluorescent material then it will absorb some amount of energy and the remaining energy is released in form of light

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ultraviolet light shining on the minerals will cause them to give off visible light.

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3 years ago
Read 2 more answers
A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.180 m2. The coil is now stretched to hav
butalik [34]

Answer:

Explanation:

Given that,

Number of turns of coil

N = 50 turns

Initial area of plane

A1 = 0.18 m²

The coil it stretch to a no area in time t = 0.1s

No area implies that the final area is 0, A2 = 0 m²

Constant magnetic field strength

B = 1.51 T

EMF?

EMF is given as

Using far away Lenz law

ε = —N• dΦ/dt

Where Φ = BA

Then,

ε = —N• d(BA)/dt

Since B is constant,

ε = —N•B dA/dt

ε = —N•B (∆A/∆t)

ε = —N•B(A2—A1)/(t2-t1)

ε = —50 × 1.51 (0—0.18)/(0.1—0)

ε =—75.5 × —0.18 / 0.1

ε = 135.9 V

The induced EMF is 135.9V

Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.

Since the area lines in the plane, then the induced emf will be out of the page

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Answer:

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