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Likurg_2 [28]
3 years ago
8

You are wearing earbuds or headphones to listen to your music but your family members can hear it as well. They tell you that it

's too loud and to turn it down so you don't lose your hearing. Based on what you’ve learned about loudness, how would you respond to your family members?
Physics
1 answer:
san4es73 [151]3 years ago
4 0

I would turn my music down some

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The decimal equivalent for meter is
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m =dm ______ 10.000

Meters

The metre is a unit of length in the metric system, and is the base unit of length in the International System of Units (SI).

As the base unit of length in the SI and other m.k.s. systems (based around metres, kilograms and seconds) the metres is used to help derive other units of measurement such as the newton, for force.

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3 years ago
An atom of sodium-23 (atomic number = 11) has a positive charge of +1. Given this information, how many
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It has a 10 electrons. Since it's atomic number is 11 it must have 11 protons. Also, given that it has a +1 charge, it has one less electron than protons since they have equal but opposite charges. The number of protons is the mass number minus the atomic number = 23-11= 12 neutrons.
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3 years ago
A 0.07 kg tennis ball, initially at rest, leaves a racket with a speed of 56 m/s. If the ball is in contact with
Naddika [18.5K]

The average force on the ball by the racket is 98 N. The correct option is the third option - 98 N

From the question, we are to determine the average force on the ball by the racket.

From the formula,

F = \frac{mv}{t}

Where F is the force

m is the mass

v is the velocity

and t is the time

From the given information

m = 0.07 kg

v = 56 m/s

t = 0.04 s

Putting the parameters into the formula,

we get

F = \frac{0.07 \times 56}{0.04}

F = \frac{3.92}{0.04}

F = 98 N

Hence, the average force on the ball by the racket is 98 N. The correct option is the third option - 98 N

Learn more on calculating force exerted on an object here: brainly.com/question/13590154

4 0
2 years ago
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2 years ago
Which factors affect gravitational potential force but not elastic potential energy
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Answer:

The mass of the object involved and the value of the gravitational acceleration

Explanation:

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- Elastic potential energy is defined as the energy possessed by an elastic object and it is given as:

U=\frac{1}{2}kx^2

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As we can see from the equations, both types of energy depends on the relative position of the object/end of the spring with respect to a certain reference position (h in the first formula, x in the second formula), but gravitational potential energy also depends on m (the mass) and g (the gravitational acceleration) while the elastic energy does not.

3 0
3 years ago
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