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blsea [12.9K]
3 years ago
5

A tennis ball of mass 57 g travels with velocity < 74, 0, 0 > m/s toward a wall. After bouncing off the wall, the tennis b

all is observed to be traveling with velocity < -70, 0, 0 > m/s.
What is the change in the magnitude of the tennis ball's momentum?
Physics
1 answer:
Sever21 [200]3 years ago
5 0

Answer:

0.228 kgm/s

Explanation:

57 g = 0.057 kg

The momentum of the tennis ball before hitting the wall is the product of its velocity and mass

p_1 = mv_1 = 0.057 * 74 = 4.218 kgm/s

The momentum of the tennis ball after hitting the wall is

p_2 = mv_2 = 0.057 * (-70) = -3.99 kgm/s

We we want to calculate the change in magnitude of the momentum, we take the difference between their absolute values:

\Delta p = |p_1| - |p_2| = 4.218 - 3.99 =0.228 kgm/s

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From equation (1), r₁ is:

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I hope it helps you!

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