Answer:
<h3>
2.3125m/s²</h3>
Explanation:
Using the equation of motion v² = u²+2aS
v is the final velocity = 120km/hr
120km/hr = 120 * 1000/1 * 3600 = 33.3m/s
u is the initial velocity = 0m/s
a is the acceleration
S is the distance covered = 240m
On substituting the given parameters
33.3² = 0²+2a(240)
33.3² = 480a
1110 = 480a
a = 1110/480
a = 2.3125m/s²
Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²
Explanation:
Visible light is a very part of electromagnetic spectrum. We can see the visible region of the electromagnetic spectrum.
The frequency and the wavelength has an inverse relationship.
For example, the red light has large wavelength and low frequency. Violet has a short wavelength and higher frequency.
The frequency range of visible region is from 400 nm to 700 nm.
Answer:
a) Magnitude of maximum emf induced = 0.0714 V = 71.4 mv
b) Maximum current through the bulb = 0.00793 A = 7.93 mA
Explanation:
a) The induced emf from Faraday's law of electromagnetic induction is related to angular velocity through
E = NABw sin wt
The maximum emf occurs when (sin wt) = 1
Maximum Emf = NABw
N = 1
A = 4 cm² = 0.0004 m²
B = 6 T
w = (284/60) × 2π = 29.75 rad/s
E(max) = 1×0.0004×6×29.75 = 0.0714 V = 71.4 mV
Note that: since we're after only the magnitude of the induced emf, the minus sign that indicates that the induced emf is 8n the direction opposite to the change in magnetic flux, is ignored for this question.
b) Maximum current through the bulb
E(max) = I(max) × R
R = 9 ohms
E(max) = 0.0714 V
I(max) = ?
0.0714 = I(max) × 9
I(max) = (0.0714/9) = 0.00793 A = 7.93 mA
Hope this Helps!!
Answer:
The decided by staring at and observing the stars.
Explanation:
Τ = Iα (torque equation)
Moment of inertia of disc about axis perpendicular to the plane of disc and passing through its centre = MR²/2
∴ 12 = MR²/2 × 5.7
∴ 12 = M(0.5)²/2 × 5.7
∴ M = 12 × 2 /5.7 × 0.5² = 16.84 Kg