Answer:
kg, mg. 65.00, 65,000,000. 65.01, 65,010,000. 65.02, 65,020,000. 65.03, 65,030,000. 65.04, 65,040,000. 65.05, 65,050,000. 65.06, 65,060,000.
Explanation:
<u>Answer:</u> The beta-particle is being released in the reaction and the nucleus is changing from to nitrogen.
<u>Explanation:</u>
Carbon-14 undergoes a radioactive decay by the process of beta-minus decay.
In beta-minus decay, a neutron gets converted to a proton and an electron.
The equation for the beta-minus decay of carbon-14 follows the reaction:
In this reaction beta-particle is being released carrying -1 charge. Another name for this particle is known as electron.
In this decay process, the nucleus is changing from carbon to nitrogen. The property of the nucleus is changing completely as number of protons is getting increased.
It is a <u><em>chemical compound</em></u> formed with a metal (mainly positive cations) with oxygen.
It is formed through the air as they react in the air together.
They are also BASES - ALKALINE (so neutralise acids)
Answer:
-2.80 × 10³ kJ/mol
Explanation:
According to the law of conservation of energy, the sum of the heat absorbed by the bomb calorimeter (Qcal) and the heat released by the combustion of the glucose (Qcomb) is zero.
Qcal + Qcomb = 0
Qcomb = - Qcal [1]
We can calculate the heat absorbed by the bomb calorimeter using the following expression.
Qcal = C × ΔT = 4.30 kJ/°C × (29.51°C - 22.71°C) = 29.2 kJ
where,
C: heat capacity of the calorimeter
ΔT: change in the temperature
From [1],
Qcomb = - Qcal = -29.2 kJ
The internal energy change (ΔU), for the combustion of 1.877 g of glucose (MW 180.16 g/mol) is:
ΔU = -29.2 kJ/1.877 g × 180.16 g/mol = -2.80 × 10³ kJ/mol
