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Katarina [22]
3 years ago
10

An atom of an element has 5 electrons in L-shell.

Chemistry
1 answer:
pishuonlain [190]3 years ago
6 0
I dont know your question but that is true
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You have 0.21 moles of Al how many atoms do you have
ZanzabumX [31]

Number of atoms : 1.26 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

0.21 moles of Al, so n = 0.21

Number of atoms :

\tt N=0.21\times 6.02\times 10^{23}\\\\N=1.26\times 10^{23}

8 0
2 years ago
The mass of a substance per unit volume
Wittaler [7]
The mass of a substance per unit volume is the substance's density.

D = m/v.
5 0
3 years ago
What is the charge of the nucleus in an Adam of oxygen -17
Ivenika [448]
Charge of nucleus is always positive whether it is element or isotope.
5 0
3 years ago
The reaction between zinc (Zn) and hydrogen chloride (HCl) produces zinc chloride (ZnCl), hydrogen (H2) gas, and heat. If more h
andrew-mc [135]

 If more   heat  is removed from the reaction the rate of reaction change as below to counter the action

The rate of the  <em>forward reaction increase</em> and produces more   <em>zinc chloride</em>


<u><em>      explanation</em></u>

  • <u><em> </em></u>The reaction of  zinc and HCl  to produce ZnCl and H2 <u><em>is </em></u> exothermic reaction,  heat  is produced as one product   and by  removing  heat  it favor   forward reaction
  • The position  of equilibrium  moves to the right since  removing  heat led to decrease of temperature  and more  zinc chloride   is produced.
6 0
3 years ago
If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor
Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

=0.658 moles NaF

16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

0.658 moles NaF x (41.99 grams NaF/ 1 mole NaF)= 27.6 moles NaF

27.6 moles of NaF would be theoretically produced.

8 0
3 years ago
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