The answers to the questions are as follows;
- It would gain three electrons
- The difference in their electronegativities.
- The elements have filled Valence levels
- potassium (K) with a 1+ charge
- ClO-
Question 1:
- How would the electron configuration of nitrogen change to make a stable configuration?
Since Nitrogen has 5 Valence electrons, it needs 3 electrons to attain it's octet configuration. As such, it gains 3 electrons.
Question 2:
- Which quantity determines how two atoms bond.
The quantity which determines how two atoms bond is The difference in their electronegativities.
Question 3:
- Which statement best explains why the elements in Group 18 do not have electronegativity values.
This is because the elements have filled Valence levels.
Question 4:
- Based on patterns in the periodic table, which ion has a stable valence electron configuration
The ion which has a stable Valence electron configuration is potassium (K) with a 1+ charge
Question 5;
- Which chemical formula represents a polyatomic ion?
The chemical formula which represents a polyatomic ion is; ClO-
The atomic mass of a carbon isotope that has 6 protons and 7 neutrons is<u> </u><u>13</u>
Explanation:
Remember that whilst the atomic number represents the number of protons in an atom, the mass number represents the summation of protons and neutrons particles in the atomic nuclei. Therefore, in this case, the carbon will have a mass number of;
6 + 7 = 13
Isotopes of an element usually have the same atomic number but different mass numbers -because they have slightly different numbers of neutrons. An example is isotopes of Carbon; C-14 and C-12
Meteoroid i’m pretty sure
manganese The metal that is used as a sacrificial electrode to prevent the rusting of iron is manganese.
Answer:
a) Li2CO3
b) NaCLO4
c) Ba(OH)2
d) (NH4)2CO3
e) H2SO4
f) Ca(CH3COO)2
g) Mg3(PO4)2
f) Na2SO3
Explanation:
a) 2Li + CO3 ↔ Li2CO3
b) NaOH * HCLO4 ↔ NaCLO4 + H2O
c) Ba + 2H2O ↔ Ba(OH)2 +
d) 2NH4 + H2CO3 ↔ (NH4)2CO3 + H2O
c) SO2 + NO2 +H2O ↔ H2SO4 + NOx
f) 2CH3COOH + CaO ↔ Ca(CH3COOH)2 + H2O
g) 3MgO + 2H3PO4 ↔ Mg3(PO4)2 + H2O
h) NaOH + H2SO3 ↔ Na2SO3 + H2O
