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meriva
3 years ago
11

1 Item 1 Item 1 1.25 points circular ceramic plate that can be modeled as a blackbody is being heated by an electrical heater. T

he plate is 30 cm in diameter and is situated in a surrounding ambient temperature of 15°C where the natural convection heat transfer coefficient is 12 W/m2·K. If the efficiency of the electrical heater to transfer heat to the plate is 80%, determine the electric power that the heater needs to keep the surface temperature of the plate at 180°C
Physics
1 answer:
Elena L [17]3 years ago
6 0

Answer:

174.85 W

Explanation:

Area of plate = 3.14 x (15x 10⁻²)²

= 706.5 x 10⁻⁴ m²

heat being radiated by convection = 12 x 706.5 x 10⁻⁴ ( 180 - 15 )

= 139.88 W. This energy needs to be fed by heat source to maintain a constant temperature of 180 degree.

If power of electric source is P

P x .8 = 139.88

P = 139.88 / .8

= 174.85 W

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If a 15-ohm resistor is connected in parallel with a 30 ohm-resistor, the equivalent resistance is?
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Answer:

Explanation:

in parallel combination equivalent resistence =

1/R=1/R1 + 1/R2

1/2=1/15+1/30

1/2=1*2+1*1/30

1/R=3/30

R*3=30*1

R=30/3

R=10 ohm

8 0
3 years ago
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In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let's find out by doing a
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Answer:

v= \frac{10\times10^{-3} V}{70} m/s

Explanation:

Assumption: bullet leaves the muzzle at a speed of V m/s

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therefore,

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⇒70×v= 10×10^-3 ×V

solving the above eqaution we get

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4 years ago
A block of 250-mm length and 48 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
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Answer:

153.6 kN

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0.12% of the original length is:

0.0012 * 0.25 m = 0.0003  m

Hooke's law:

F = x * k

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F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)

The compressive load will generate a stress of

σ = F / A

F = σ * A

F = 80*10^6 * 0.048 * 0.04 = 153.6 kN

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3 years ago
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banked designed for traffic moving at 58 km/h\approx 16.11 m/s

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\mu =\frac{1.2804-0.5202}{9.726+0.068}

\mu =0.077

7 0
3 years ago
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