Answer:
Explanation:
in parallel combination equivalent resistence =
1/R=1/R1 + 1/R2
1/2=1/15+1/30
1/2=1*2+1*1/30
1/R=3/30
R*3=30*1
R=30/3
R=10 ohm
Answer:
m/s
Explanation:
Assumption: bullet leaves the muzzle at a speed of V m/s
and velocity of push received by the man be v m/s
According to newton's third law to every action there is always an equal and opposite reaction.
therefore,
mass of man× velocity = mass of bullet×its velocity
⇒70×v= 10×10^-3 ×V
solving the above eqaution we get
therefore
m/s
Answer:
153.6 kN
Explanation:
The elastic constant k of the block is
k = E * A/l
k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m
0.12% of the original length is:
0.0012 * 0.25 m = 0.0003 m
Hooke's law:
F = x * k
Where x is the change in length
F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)
The compressive load will generate a stress of
σ = F / A
F = σ * A
F = 80*10^6 * 0.048 * 0.04 = 153.6 kN
The smallest admisible load is 153.6 kN
Answer:0.077
Explanation:
Given
banked designed for traffic moving at 
Radius of the curve 201 m
Actual traffic velocity =
For banking of road



Centripetal acceleration is given by

Taking component of centripetal acceleration
along and perpendicular to surface


From FBD

----1
where
is frictional force

----2
and we know coefficient of friction is given by




