HELP ME PLEASE!

1 answer:

5 0

1) 180 days. 24 hours in a day. 60 minutes in an hour. 24X60=1440. Then, take that by the days: 180. 180X1440=259,200 minutes in 180 days.

2) One English ton is 2,240 pounds. There are approximately 453.6 grams in one pound. 1.8X10^-4= .00018(2240)=.4032 TONS. To convert to pounds: .4032(2240)=903.168. To convert that to grams, multiply by the number of grams in a pound. 453.6(903.168)=409,677 grams. I apologize if I misunderstood your question (your 1.80X10-4 Tons was confusing)

3)First of all, figure out how many years 62 months is. The closest divisible is 60, which would be 5 years. So, first let's take care of the 5 years. Multiply it by the number of minutes in a year to start. 525,600(5)=2,628,000 minutes. Then multiply by 60 to get seconds: 2,628,000(60)= 157,680,000. Now, DON'T FORGET the other two months! Assuming that they are normal months (not February), they would equal 61 days (one 31 days, the other 30). The seconds in a day are 24x60x60=8,400. Multiply that by your number of days. 8,400(61)=5,270,400. DON'T FORGET TO ADD THEM TOGETHER!!! Add your two months and your 5 years: 157,680,000+5,270,400= 162,950,400 seconds!

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Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu

nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,

$Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)$

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

$E^0_{[Pb^{2+}/Pb]}=-0.13V$