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2 years ago

6

Why do high-altitude clouds tend to appear before a warm front arrives in a region?

2 answers:

Ilia_Sergeevich [38]2 years ago

8 0

Answer:

Global Warming

Explanation:

That's why

kicyunya [14]2 years ago

5 0

Cold air is more dense than warm air, so when a warm air mass meets a cold air mass, the cold air ends up below the warm air. Once the air has risen, it cools and clouds can form. Warm fronts produce clouds when warm air replaces cold air by sliding above it,

Hope this helps :)

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If a current is two amps and the resistance is 3 ohms, how much voltage was needed?

Hunter-Best [27]

Answer:

6 V

Explanation:

We can solve the problem by using Ohm's law:

$V=RI$

where

V is the voltage in the circuit

R is the resistance

I is the current

In this problem, we know the current, $I=2 A$ , and the resistance, $R=3 \Omega$ , therefore we can find the voltage in the circuit:

$V=RI=(3 \Omega )(2 A)=6 V$

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2 years ago

You want to raise the temperature of 22kg of water from 60°C to 95°C. If electricity costs $0.08/kWh, how much would it cost you

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Answer:

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Explanation:

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2 years ago

A sample of chloroform is found to contain 12.0 g of carbon, 106.4 g of chlorine, and 1.01 g of hydrogen. If a second sample of

GREYUIT [131]

Given:

Sample 1:

Chloroform is $CHCl_{3}$

12 g Carbon

1.01 g Hydrogen

106.4 g Cl

Sample 2:

30.0 g of Carbon

Solution:

mass of chloroform from sample 1:

12 + 1.01 +106.4 =119.41 g

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mass of chloroform $\times$ $\frac{given mass of carbon}{mass of carbon atom}$

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6 0

2 years ago

10. A hockey puck with mass 0.3 kg is sliding along ice that can be considered frictionless. The puck’s velocity is 20 m/s when

SVEN [57.7K]

Answer:

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Explanation:

For this case we can use the second law of Newton given by:

$\sum F = ma$

The friction force on this case is defined as :

$F_f = \mu_k N = \mu_k mg$

Where N represent the normal force, $\mu_k$ the kinetic friction coeffient and a the acceleration.

For this case we can assume that the only force is the friction force and we have:

$F_f = ma$

Replacing the friction force we got:

$\mu_k mg = ma$

We can cancel the mass and we have:

$a = \mu_k g = 0.35 *9.8 \frac{m}{s^2}= 3.43 \frac{m}{s^2}$

And now we can use the following kinematic formula in order to find the distance travelled:

$v^2_f = v^2_i - 2ad$

Assuming the final velocity is 0 we can find the distance like this:

$d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m$

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3 years ago

A duck flies 60 m in 6 seconds what is the ducks speed? Show your work plz

Lana71 [14]

Answer:

Wouldn’t his or hers speed be 10m?

Explanation:

because 60 divided by 6 = 10

so 10m per second?

7 0

2 years ago