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qwelly [4]
2 years ago
6

Why do high-altitude clouds tend to appear before a warm front arrives in a region?

Physics
2 answers:
Ilia_Sergeevich [38]2 years ago
8 0

Answer:

Global Warming

Explanation:

That's why

kicyunya [14]2 years ago
5 0
Cold air is more dense than warm air, so when a warm air mass meets a cold air mass, the cold air ends up below the warm air. Once the air has risen, it cools and clouds can form. Warm fronts produce clouds when warm air replaces cold air by sliding above it,

Hope this helps :)
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I need help on 18,19,20 and 21
Dmitriy789 [7]
When a relationship between two different things is shown in a fraction it is a ratio.

hope this helps :)



8 0
3 years ago
A farmhand attaches a 25-kg bale of hay to one end of a rope passing over a
Georgia [21]

Explanation:

Newton's second law:

∑F = ma

277 N − 245 N = (25 kg) a

a = 1.28 m/s²

8 0
2 years ago
43 kg bear slides, from rest, 15 m down a lodgepole pine tree, moving with a speed of 5.5 m/s just before hitting the ground. (a
olga2289 [7]

Answer:

-6327.45 Joules

650.375 Joules

378.47166 N

Explanation:

h = Height the bear slides from = 15 m

m = Mass of bear = 43 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of bear = 5.5 m/s

f = Frictional force

Potential energy is given by

P=mgh\\\Rightarrow P=43\times -9.81\times 15\\\Rightarrow P=-6327.45\ J

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules

Kinetic energy is given by

K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 43\times 5.5^2\\\Rightarrow K=650.375\ J

Kinetic energy of the bear just before hitting the ground is 650.375 Joules

Change in total energy is given by

\Delta E=fh=-(\Delta K+\Delta P)\\\Rightarrow fh=-(650.375-6327.45)\\\Rightarrow fh=5677.075\\\Rightarrow f=\frac{5677.075}{h}\\\Rightarrow f=\frac{5677.075}{15}\\\Rightarrow f=378.47166\ N

The frictional force that acts on the sliding bear is 378.47166 N

5 0
3 years ago
Read 2 more answers
Find the distance covered by a car in 10 second, if it is moving at the speed of 20m/s​
labwork [276]

Answer:

solution

we know that .

s=ut+½at²

now, putting the values in the second equation of motion ,

we get,

S=20×10+1/2×(10)²

S=200+1×100

S=200+100

S=300m

the distance covered by given body or object in 10 seconds is 300 m.

8 0
3 years ago
Help plzz!!
frez [133]

Answer: It would be 125 J

4 0
2 years ago
Read 2 more answers
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