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2 years ago

How do you find the value of e?

Physics

1 answer:

Nadusha1986 [10]2 years ago

3 0

<h3>Answer: 22.48°</h3><h3 /><h3>Explanation:</h3>

refractive index = sin i / sin e

where i is the angle of incidence

e is the angle of refraction

1.5 = sin 35 / sin e

1.5 = 0.5736/sin e

sin e = 0.5736/ 1.5

sin e = 0.3824

e = 22.48°

<h3 />

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The electromagnetic wave that delivers a cellular phone callto

spin [16.1K]

Answer:

$E=2.41\cdot 10^{-5} J$

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

$I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}}$ (1)

c is the speed of light (3*10⁸ m/s)
μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
B₀ is the magnetic field

$I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}$

$I_{average}=2.68\cdot 10^{-6} W/m^{2}$

Now, let's define the relationship between power (P) and average intensity (I).

$I_{average}=\frac{P}{A}$

P is the power
A is the area crossed

So we can calculate the power.

$P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W$

Finally, energy is the product of P times time, so:

$E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J$

I hope it helps you!

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2 years ago

The equation below is used to calculate the mechanical advantage of an ideal wheel and axle.

Jet001 [13]

Answer:

Explanation:

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2 years ago

You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using e

Mashutka [201]

You are working for a manufacturing company, which is mathematically given as

$m=3\sqrt{2}$
$m=\frac{15\sqrt{5}}{16}$
x=0.747a
$m/n=\frac{(x^2+a^2)3/2}{x^3}$

<h3>What is the value of m that will place the movable bead in equilibrium at x-a a ....?</h3>

Generally, the equation for the force of equilibrium is mathematically given as

F=2fcos\theta

Therefore

$K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3$

$m=3\sqrt{2}$

By force equilibrium

$K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}$

Therefore

$n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\$

$m=\frac{15\sqrt{5}}{16}$

$K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}$

x^2+a^2=(14/3)^{2/3}x^2

x=a/1.338

x=0.747a

By force equilibrium

$K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}$

$m/n=\frac{(x^2+a^2)3/2}{x^3}$