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Airida [17]
3 years ago
14

El trabajo hecho por la gravedad durante el descenso de un proyectil es:

Physics
1 answer:
Ket [755]3 years ago
5 0

Answer:

<h2>a) positivo.</h2>

Explanation:

The question is

The work done by gravity during a projectile decline is:

a) Positive.

b) Negative.

c) Zero.

d) Depends on y-axis direction.

e) Depends on x-axis direciton.

Remember that Work is defined as the energy needed to move an object. Mathematically, it's the product between the force exerted and the displacement. That means if we don't have any displacement, then there's no work.

In this case, we are talking about the work done by the gravity force. When a projectile goes down, it's because of the gravity force, which means it can't be zero.

Specifically, the work done by gravity is positive, because when the projectile is going down, it's getting closer to the atracttive mass, which is Earth.

Therefore, the right answer is a.

You might be interested in
Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and th
Ket [755]

Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Explanation:

Given:

Unpolarized light of intensity (I₀) = 950 W/m²

θ = 65°

Find:

a. Intensity of the light (first polarizer)

b. Intensity of the light (second polarizer)

Computation:

a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

Intensity of the light (first polarizer) (I₁) = 950 / 2

Intensity of the light (first polarizer) (I₁) = 425 W/m²

b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

5 0
3 years ago
There. That is better.
mihalych1998 [28]

a
a
b
b
a
b
a
This will really help you learn a lot.

6 0
3 years ago
At the local swimming hole, a favorite trick is to run horizontally off a cliff that is 8.0 m above the water. One diver runs of
Alika [10]

Answer:

Number of revolutions=1.532 revolutions

Explanation:

Given data

Distance s=8.0 m

Angular speed a=1.2 rev/s

To find

Number of revolutions

Solution

From the equation of simple motion we not that

S=ut+1/2gt^{2}\\ where\\u=0\\So\\8.0m=0+(1/2)(9.8m/s^{2} )t^{2}\\ t^{2}=\frac{8.0m}{0.5*9.8m/s^{2} } \\ t^{2}=1.63\\t=\sqrt{1.63} \\t=1.28s

So for the number of revolutions she makes is given as

n=a*t\\n=(1.2rev/s)(1.28s)\\n=1.532revolutions

8 0
3 years ago
800 joules of work were done with a force of 200 newtons. Over what
Svetach [21]

Answer:

4m

Explanation:

800/200

7 0
3 years ago
Need help with this plz
Lisa [10]

Answer:

1 - amplification

3- actinide

5 - radioactive decay ( im not really sure on this one )

7- alternating current

Explanation:

7 0
3 years ago
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