Answer:
Wavelength,
Explanation:
Given that,
Speed of the sound in the rat tissues, v = 1500 m/s
Let is the wavelength of an ultrasonic wave. The speed of a wave is given by the relation as follows:
Let us assume that the frequency of ultrasonic wave is 2.3 MHz.
So, the wavelength of an ultrasonic wave is . Hence, this is the required solution.
Answer:
electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.
Answer:
5.065 Ohm, 1.935 Ohm
Explanation:
when the resistors are connected in series.
Rs = R1 + R2
by using Ohm's law
V = I Rs
12.7 = 1.81 x Rs
So, R1 + R2 = 7 Ohm ...... (1)
When the resistors are connected in parallel.
Rp = R1 x R2 / (R1 + R2)
Using Ohm's law
V = I Rp
12.7 = 9.06 x Rp
R1 x R2 / (R1 + R2) = 1.4 ohm
Substitute the value of R1 + R2 from equation (1)
R1 x R2 = 1.4 x 7
R1 x R2 = 9.8
R1 - R2 = 3.13 Ohm ......(2)
By solving equation (1) and equation (), we get
R1 = 5.065 Ohm
R2 = 1.935 Ohm
The answer is C hope it helps !
Answer:
1.424 μC
Explanation:
I'm assuming here, that the charged ball is suspended by the string. If the string also is deflected by the angle α, then the forces acting on it would be: mg (acting downwards),
tension T (acting along the string - to the pivot point), and
F (electric force – acting along the line connecting the charges).
We then have something like this
x: T•sin α = F,
y: T•cosα = mg.
Dividing the first one by the second one we have
T•sin α/ T•cosα = F/mg, ultimately,
tan α = F/mg.
Since we already know that
q1=q2=q, and
r=2•L•sinα,
k=9•10^9 N•m²/C²
Remember,
F =k•q1•q2/r², if we substitute for r, we have
F = k•q²/(2•L•sinα)².
tan α = F/mg =
= k•q²/(2•L•sinα)² •mg.
q = (2•L•sinα) • √(m•g•tanα/k)=
=(2•0.5•0.486) • √(0.0142•9.8•0.557/9•10^9) =
q = 0.486 • √(8.61•10^-12)
q = 0.486 • 2.93•10^-6
q = 1.424•10^-6 C
q = 1.424 μC.