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Rainbow [258]
4 years ago
12

A diver who weighs 500 N steps off a diving board that is 10 m above the water. The diver hits the water with kinetic energy of

8) _______ A) 10 J. B) 500 J. C) 5000 J. D) more than 5000 J. E) 510 J.
Physics
1 answer:
pentagon [3]4 years ago
7 0

Answer:

C) 5000 J

Explanation:

when diver is at some height , he is having some energy in the form of potential energy. when he dives, his potential energy is converted into kinetic energy . so kinetic energy and potential energy are equal.

Kinetic energy of diver = potential energy of diver

= mgh

= 500 x 10

= 5000 J .

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Answer is D. Neutral charge
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What are the wavelengths of electromagnetic wave in free space that have the following frequencies?.
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The wavelengths of the light are 4.3 * 10^-12 m and 0.2 m respectively.

<h3>What is wavelength?</h3>

The term wavelength has to do with the horizontal distance that is covered by a wave. We know that a long wavelength implies that the wave is able to travel a long distance from one point to another.

Given that;

c = λf

c = speed of light

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Thus;

λ = 3 * 10^8/ 7.00 x 10^19

λ = 4.3 * 10^-12 m

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λ = 2 * 10^-1 or 0.2 m

Learn more about wavelength:brainly.com/question/13533093

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Missing parts:

What are the wavelengths of electromagnetic wave in free space that have the following frequencies? (a) 7.00 x 10^19 Hz______ pm (b) 1.50 x 10^9 Hz__________ cm

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Strictly speaking, will a penny be slightly more massive if it has a negative charge or a positive charge? discuss.
Alex_Xolod [135]
<span>A negatively charged penny is one with extra electrons, which would increase its mass ever so slightly compared to a positively charged penny, or one with a lack of electrons.</span>
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How to find kinetic energy
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The animation shows a ball which has been kicked upward at an angle. Run the animation to watch the motion of the ball. Click in
sergejj [24]

Answer:

The acceleration of the ball is  a_y =  - 0.3672 \ m/s^2

Explanation:

From the question we are told that

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The vertically motion of the ball can be mathematically represented as

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Here the final velocity at the maximum height is zero so v_{fy} = 0 \ m/s

Making the acceleration a_y the subject we have

        a_y =  \frac{v_{iy} ^2}{2H_{max}}

substituting values

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