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Rainbow [258]
3 years ago
12

A diver who weighs 500 N steps off a diving board that is 10 m above the water. The diver hits the water with kinetic energy of

8) _______ A) 10 J. B) 500 J. C) 5000 J. D) more than 5000 J. E) 510 J.
Physics
1 answer:
pentagon [3]3 years ago
7 0

Answer:

C) 5000 J

Explanation:

when diver is at some height , he is having some energy in the form of potential energy. when he dives, his potential energy is converted into kinetic energy . so kinetic energy and potential energy are equal.

Kinetic energy of diver = potential energy of diver

= mgh

= 500 x 10

= 5000 J .

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What structures can be found in the axial region of the body?
Softa [21]

Answer:

The axial region of the body consists of the bones of the head, trunk of a vertebrate, skull, vertebral column, and thoracic cage. The human skeleton consists of 80 bones.

Explanation:

The axial region of the body consists of the bones of the head, trunk of a vertebrate, skull, vertebral column, and thoracic cage. The human skeleton consists of 80 bones.

It is composed of the following six parts:

1. Skull (22 bones)

2. Ossicles of the middle ear

3. Hyoid bone

4. Rib cage

5. Sternum

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3 years ago
What is newton's 3rd law of physics ​
ValentinkaMS [17]

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

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3 years ago
What would be new resistance if length of conductor is doubled and thickness is halved <br>​
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3 years ago
Two negative charges that are both - 3.8 C push each other apart with a force of 19.0 N. How far apart are the two charges?
77julia77 [94]

Answer:

The separation distance between the two charges must be 82704.2925 m

Explanation:

Given:

Two negative charges that are both q = -3.8 C

Force of 19 N

Question: How far apart are the two charges, s = ?

First, you need to get the electrostatic force of this two negative charges:

F=\frac{kq}{s^{2} } \\s=\sqrt{\frac{kq}{F} }

Here

k = electric constant of the medium = 9x10⁹N m²/C²

Substituting values:

s=\sqrt{\frac{9x10^{9}*(-3.8)^{2}  }{19} } =82704.2925m

7 0
3 years ago
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