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3 years ago

5. How does a jack make changing a tire easier?

Physics

1 answer:

strojnjashka [21]3 years ago

4 0

Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.

Explanation:

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An echo is an example of sound wave A) diffraction. B) interference. C) reflection. D) refraction.

DedPeter [7]

It is an example of reflection of wave. C.

6 0

3 years ago

Read 2 more answers

When numbers are very small or very large, it is convenient to either express the value in scientific notation and/or by using a

Oxana [17]

Answer:

5 mg, $5\cdot 10^{-3}g$

Explanation:

First of all, let's rewrite the mass in grams using scientific notation.

we have:

m = 0.005 g

To rewrite it in scientific notation, we must count by how many digits we have to move the dot on the right - in this case three. So in scientific notation is

$m=5\cdot 10^{-3}g$

If we want to convert into milligrams, we must remind that

1 g = 1000 mg

So we can use the proportion

$1 g : 1000 mg = 0.005 g : x$

and we find

$x=\frac{(1000 mg)(0.005 g)}{1 g}=5 mg$

4 0

3 years ago

An 88 kg worker stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale reads 900 N. Fi

Aleks [24]

Answer:

The magnitude is "3.8 m/s²", in the upward direction.

Explanation:

The given values are:

Mass,

m = 88 kg

Scale reads,

T = 900 N

As we know,

⇒ $N=mg$

On substituting the given values, we get

⇒ $=88\times 9.8$

⇒ $=862.4 \ N$

Now,

⇒ $T=mg-ma$

On substituting the given values in the above equation, we get

⇒ $900=862.4-9.8 a$

On subtracting "862.4" from both sides, we get

⇒ $900-862.4=862.4-9.8 a-862.4$

⇒ $37.6=-9.8a$

⇒ $a=-\frac{37.6}{9.8}$

⇒ $a=3.8 \ m/s^2$ (upward direction)

8 0

3 years ago

During their physics field trip to the amusement park, Leslie and Maria took a ride on the Whirligig. The Whirligig ride consist

grandymaker [24]

Answer:

a) frequency = 0.1724 Hz

b) Period = 5.8 sec

c) speed = 7.04 m/s

d) acceleration = 7.62 m/s²

Explanation:

Given that;

radius = 6.5m

time period = 5.8 sec every circle

a) the frequency

frequency is the number of rotation in unit time

frequency = 1 / time period = 1/5.8

frequency = 0.1724 Hz

b) the period

period is time taken in one rotation

period = total time / rotation = 5.8 / 1

Period = 5.8 sec

c) the speed

speed = distance/time = circumference/time period = 2πr / t = (2π×6.5) / 5.8

speed = 7.04 m/s

d) acceleration

To find the acceleration we take the linear velocity squared divided by the radius of the circle.

acceleration = v² / r = (7.04)² / 6.5 = 49.5616 / 6.5

acceleration = 7.62 m/s²

6 0

3 years ago

A physics professor wants to perform a lecture demonstration of Young's double-slit experiment for her class using the 633-nm li

Alexeev081 [22]

Note: if the professor wants the distance between the m = 0 and m = 1 maxima to be 25 cm

Answer:

d = 1.0128×10⁻⁵m

Explanation:

given:

length L = 4.0m

maximum distance between m = 0 and m = 1 , y = 25cm = 0.25m

wavelength λ = 633nm = 633×10⁻⁹m

note:

dsinθ = mλ (constructive interference)

where d is slit seperation, θ is angle of seperation , m is order of interference , and λ is wavelength

for small angle

sinθ ≈ tanθ

$d (\frac{y}{L}) =$ mλ

$d (\frac{y}{L}) = (1)(633nm)$

$d(\frac{0.25}{4} ) = (1)(633nm)$

d = 1.0128×10⁻⁵m

6 0

3 years ago