Answer:
Explanation:
Not enough information.
IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.
THEN
The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was
v = gt
vy₀ = 9.8(0.5)
vy₀ = 4.9 m/s
vsinθ = vy₀
v = vy₀/sinθ
v = 4.9/sin32
v = 9.2466...
v = 9.2 m/s
Hence the expression of ω in terms of m and k is
Given the expressions;
Equating both expressions we will have;
Divide both equations by 2π
Square both sides
Take the square root of both sides
Hence the expression of ω in terms of m and k is
Answer:
उव्ग्वुव ह्व्झ एउएइहे एइएइएइएएइ सिसुब्स्सी बीस सिस इस्ब एइब
Explanation:
?उग्व्ब्वु विब्सिए इसिग्व विद्बिअब्द सिह्व्व इस्ब्व दिव्ब्स विह्द ऐद्जिइ सुउगव्दी सिइगैगे क्ज्गैइव अजिव्व्ज्व्स कैह्द अजि ह्ज्फ्ज इअह इकुगै ईग इअबे अजिव्ब जैइअब इऐहे ऐइहे ऐइग्गे अत्व्ब ओप्झब रोज दिधिए ऊइफ्ब इसुहद ईउहे सिउउअ दिइब्द स्सिउए ऐइहे सिएय्व एउविये एइव्वे
Answer:
The work done against gravity is 78.4 J
Explanation:
The work is calculated by multiplying the force by the distance that the
object moves
W = F × d, where W is the work , F is the force and d is the distance
The SI unit of work is the joule (J)
We need to find the work done against gravity when lowering a
16 kg box 0.50 m
→ F = mg
→ m = 16 kg, and g = 9.8 m/s²
Substitute these value in the rule
→ F = 16 × 9.8 = 156.8 N
→ W = F × d
→ F = 156.8 N and d = 0.50
Substitute these values in the rule
→ W = 78.4 J
<em>The work done against gravity is 78.4 J</em>
