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dmitriy555 [2]
3 years ago
8

HELP!

Engineering
1 answer:
olya-2409 [2.1K]3 years ago
5 0
The thickness is thick
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Consider incompressible flow in a circular channel. Derive general expressions for Reynolds number in terms of (a) volume flow r
Georgia [21]

Answer:

a) Re = \frac{4\cdot \rho \cdot Q}{\pi\cdot \mu\cdot D}, b) Re = \frac{4\cdot \dot m}{\pi\cdot \mu\cdot D}, c) 1600

Explanation:

a) The Reynolds Number is modelled after the following formula:

Re = \frac{\rho \cdot v \cdot D}{\mu}

Where:

\rho - Fluid density.

\mu - Dynamics viscosity.

D - Diameter of the tube.

v - Fluid speed.

The formula can be expanded as follows:

Re = \frac{\rho \cdot \frac{4Q}{\pi\cdot D^{2}}\cdot D }{\mu}

Re = \frac{4\cdot \rho \cdot Q}{\pi\cdot \mu\cdot D}

b) The Reynolds Number has this alternative form:

Re = \frac{4\cdot \dot m}{\pi\cdot \mu\cdot D}

c) Since the diameter is the same than original tube, the Reynolds number is 1600.

8 0
3 years ago
Which of the following results from the fact that skip signals refracted from the ionosphere are elliptically polarized?
zhenek [66]

Answer:

B

Explanation:

The fact that skip signals refracted from the ionosphere are elliptically polarized is a result of either vertically or horizontally polarized antennas may be used for transmission or reception.

8 0
3 years ago
If the two 304-stainless-steel carriage bolts of the clamp each have a diameter of 10 mmmm, and they hold the cylinder snug with
S_A_V [24]

Answer: hello some data related to your question is missing attached below is the missing data

answer:

T2 = 265°C

Explanation:

First step : calculate sum of vertical forces

∑ y = 0

Fmg - 2(0.5 Fst ) = 0

∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )

          = 1884.96 N

Also determine the Compatibility equation in order to determine the change in Temperature

ΔT = 250°C

therefore Temperature at which average normal stress becomes 12.0 MPa

ΔT = T2 - T1

250°C = T2 - 15°C

T2 = 250 + 15 = 265°C

attached below is the detailed solution

4 0
3 years ago
Rewrite the following nested if-else statement as a switch statement that accomplishes exactly the same thing. Assume that num i
seropon [69]

Answer:

Answer explained below

Explanation:

The following is the nested if-else statement:

% if-based statement

if num < -2 ||  num > 4

          f1(num)

else

     if num <=2

          if num >= 0

              f2(num)

          else

              f3(num)

          end

     else

          f4(num)

     end

end

<u>NOTE:</u> the num is an integer variable that has been initialized and that there are functions f1, f2, f3 and f4.

   

The nested if-else statement can be replaced by switch statement as shown below:

switch num

    case(0, 1, 2)

         f2(num)

    case(-2, -1)

         f3(num)

    case(3, 4)

         f4(num)

    otherwise

         f1(num)

In this case, the switch based code is easier to write and understand because the cases are single valued or a few discrete values (not ranges of values)

8 0
3 years ago
Compute the fundamental natural frequency of the transverse vibration of a uniform beam of rectanqular cross section, with one e
marshall27 [118]

Answer:

The natural angular frequency of the rod is 53.56 rad/sec

Explanation:

Since the beam is free at one end and fixed at the other hence the beam is a cantilevered beam as shown in the attached figure

We know that when a unit force is placed at the end of a cantilever the displacement of the free end is given by

\Delta x=\frac{PL^3}{3EI}

Hence we can write

P=\frac{3EI\cdot \Delta x}{L^3}

Comparing with the standard spring equation F=kx we find the cantilever analogous to spring with k=\frac{3EI}{L^3}

Now the angular frequency of a spring is given by

\omega =\sqrt{\frac{k}{m}}

where

'm' is the mass of the load

Thus applying values we get

\omega _{beam}=\sqrt{\frac{\frac{3EI}{L^{3}}}{Area\times density}}

\omega _{beam}=\sqrt{\frac{\frac{3\times 20.5\times 10^{10}\times \frac{0.1\times 0.3^3}{12}}{5.9^{3}}}{0.3\times 0.1 \times 7830}}=53.56rad/sec

8 0
3 years ago
Read 2 more answers
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