Answer:

Step-by-step explanation:
35 marks out of 40<u> as a fraction:</u>
35 / 40
<u>As a percentage:</u>
<u></u>![\sf \frac{35}{40} * 100 \ \%\\\\0.875 * 100 \ \%\\\\87.5 \ \%\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cfrac%7B35%7D%7B40%7D%20%2A%20100%20%5C%20%5C%25%5C%5C%5C%5C0.875%20%2A%20100%20%5C%20%5C%25%5C%5C%5C%5C87.5%20%5C%20%5C%25%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
 
        
             
        
        
        
Answer:
2. n = 11
4. g = -2
6. t = 21
8. n = 4
10. y = -1
Step-by-step explanation:
2. 63  = -3(1 - 2n)
Dividing both the side by negative 3 we get 

4. -g + 2(3 + g) = -4(g + 1)
First we will open the bracket by distributive property A( B +C) = AB + AC

6.-3(t +5 ) + (4t + 2) = 8
Using distributive property A( B +C) = AB + AC we get

8. -8 - n = -3(2n -4)
Using distributive property A( B +C) = AB + AC we get

10. -4( 2 - y) + 3y = 3(y - 4)
Using distributive property A( B +C) = AB + AC we get

 
        
             
        
        
        
Answer:
A. 2
B. 10/3 
C. 8/3 
D. 2/3
Step-by-step explanation: put the whole #and make it into a fraction like this e.g.
6/1 • 1/3 = 6/3 simplifies to 2
 
        
             
        
        
        
Answer:
   $9,812.29
Step-by-step explanation:
The amount in Jeremy's account can be computed using the compound interest formula.
__
<h3>account value</h3>
The formula for the value of an account earning compound interest at annual rate r, compounded n times per year for t years is ...
   A = P(1 +r/n)^(nt)
where P is the principal invested.
__
<h3>formula application</h3>
When P=$8500, r=0.024, n=4, t=6, the formula becomes ...
   A = $8500(1 +0.024/4)^(4·6) = $8500(1.006^24) ≈ $9812.29
There will be $9,812.29 in this account after 6 years.
 
        
             
        
        
        
Answer:
yermin
Step-by-step explanation:
edge 2021