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VMariaS [17]
4 years ago
11

8. MD Persevere with Problems The perimeter of a rectangle

Mathematics
1 answer:
ss7ja [257]4 years ago
6 0

Answer:

Step-by-step explanation:

P = 2(L + W)

P = 24

width = x, length = y

24 = 2(x + y)

24 = 2x + 2y

standard form would be : 2x + 2y = 24, or it could also be x + y = 12

to find the x intercept, sub in 0 for y and solve for x

x + y = 12

x + 0 = 12

x = 12....so the x intercept is (12,0)

to find the y intercept, sub in 0 for x and solve for y

x + y = 12

0 + y = 12

y = 12......so the y intercept is (0,12)

No, the intercepts do not make sense.

consider the equation : 2x + 2y = 24

if x is 12.......

2(12) + 2y = 24

24 + 2y = 24

2y = 24 - 24

2y = 0

y = 0......so if x (the width) is 12 cm, the y(the length) would be 0.

same goes with the length (y)....if y = 12, then the width (x) is 0

also, if x is 12 and y is 12

P = 2(L + W)

P = 2(12 + 12)

P = 2(24)

P = 48..............then the perimeter would not be 24, it would be 48

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7

Step-by-step explanation:

9×7 = 63

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Here are the percents of the popular
kvv77 [185]

Answer: 57.4

Step-by-step explanation:

First order the numbers from the smallest to the largest:

49.6, 55.1, 57.4, 49.7, 61.1, 43.4,  60.7, 50.1, 50.7, 58.8, 53.9, 43.2,  49.2, 47.9, 51.2

to:

43.2, 43.4, 47.9, 49.2, 49.6, 49.7, 50.1, 50.7, 51.2, 53.9, 55.1, 57.4, 58.8, 60.7, 61.1.

The position of third quartile is:

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That number is:

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3 years ago
a sports team donates 157 tickets to a sporting event,with tickets to be shared equally among 9 classrooms.How many tickets does
Valentin [98]

Answer:

Each class should get 17 tickets. 4 tickets will be left over.

Step-by-step explanation:

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5 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
3 years ago
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