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STALIN [3.7K]
3 years ago
13

How would you measure the specific latent heat of vaporisation of a liquid?

Chemistry
1 answer:
son4ous [18]3 years ago
8 0

Answer:

Ramsey and Marshall method.

Explanation:

The specific latent heat of vapourization of a liquid is measured by a modification of the method of Ramsey and Marshall in the year 1896.

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Write the nuclear equation for the beta decay of Aluminum-25.
Brums [2.3K]

We want to write the nuclear equation for the beta decay of Aluminium-25.

The equation is:

^{25}_{13}Al \implies ^{25}_{14}Si +   ^{0}_{-1}e

First, as you may know, in a beta decay the number of protons is increased by one. Aluminium has 13 of them, so after the decay, we will have 14 protons.

This means that the aluminium will transform into silicon, then the nuclear equation is just:

^{25}_{13}Al \implies ^{25}_{14}Si +   ^{0}_{-1}e

Where the:

^{0}_{-1}e

Is an electron, which is the emitted particle in the beta decay.

If you want to learn more, you can read:

brainly.com/question/4184205

3 0
3 years ago
It requires two sticks of butter to make a batch of 20 cookies. How much butter will it take to make 150 cookies?
liq [111]

Answer:

It would take 15 sticks of butter

Explanation:

2 divided by 20 is 0.1

0.1 is how much butter for 1 so now we multiply that by 150

0.1 x 150 = 15

Therefore, you would need 15 sticks of butter for 150 cookies

6 0
3 years ago
Plz help me with the electron dot structures! I’ll mark brainliest!
diamong [38]
The electron dot structure for each molecule are:
.. ..
a. H:O:O:H
.. ..
The partial negative charges are on the Oxygen atoms.

..
b. H:Cl:
..
The partial negative charge is on the Chlorine atom.

..
c. H:Br:
..
The partial negative sign is on Bromine atom.

..
d. H:O:H
..
The partial negative sign is on the Oxygen atom.
8 0
3 years ago
If the stocks in a system always decrease and never increase, the system has what type of feedback loop? (Select the best answer
AlekseyPX
A psitive feedback
rawmaterial waste

6 0
3 years ago
4. A sample of nitrogen at 20 degrees Celsius was compressed to 300ml to
cricket20 [7]

Answer:

We are given:

V(i) = 0.3 L                          V(f) = 0.36 L

P(i) = x pa                            P(f) = 400 pa

T(i) = T(f) = 293 k

Using the gas formula:

PV = nRT

Since n , R and T are constant,

PV = k  (where k is a constant)

Hence we can say that:

P(i) * V(i) = P(f) * V(f)

x * 0.3 = 0.36 * 400

x = 14.4/0.3

x = 480 pascals

Hence the initial pressure is 480 pascals

Converting to Kpa, we have to divide by 1000

Initial pressure (Kpa) = 0.48

3 0
4 years ago
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