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STALIN [3.7K]
3 years ago
13

How would you measure the specific latent heat of vaporisation of a liquid?

Chemistry
1 answer:
son4ous [18]3 years ago
8 0

Answer:

Ramsey and Marshall method.

Explanation:

The specific latent heat of vapourization of a liquid is measured by a modification of the method of Ramsey and Marshall in the year 1896.

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A calorimeter contains 100 g of water at 39.8 ºC. A 8.23 g object at 50 ºC is placed inside the calorimeter. When equilibrium ha
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When equilibrium has been reached so, according to this formula we can get the specific heat of the unknown metal and from it, we can define the metal as each metal has its specific heat:

Mw*Cw*ΔTw = Mm*Cm*ΔTm

when 
Mw → mass of water
Cw → specific heat of water
ΔTw → difference in temperature for water 

Mm→ mass of metal
Cw→ specific heat of the metal
ΔTm → difference in temperature for metal

by substitution:

100g * 4.18 * (40-39.8) = 8.23 g * Cm * (50-40)

∴ Cm = 83.6 / 82.3 = 1.02 J/g.°C

when the Cm of the Magnesium ∴ the unknown metal is Mg
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Sarah rolls a ball in the grass. The ball starts off moving quickly, starts to slow down, and eventually stops. Using the words
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Answer:

hi 5th grader, stop trying to cheat :)

Explanation:

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3 years ago
The North Star is the last star in the Ursa Minor constellation.<br> True<br> False
Alja [10]
The answer is true. It is the last star.
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Determine the mechanical energy of this object: a 1-kg ball sits on a 10-meter high cliff.
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Mechanical energy = mass x acceleration due to gravity x height 
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One of the reactions in a blast furnace used to reduce iron is shown above. How many grams of Fe2O3 are required to produce 15.5
Salsk061 [2.6K]

Answer : The correct option is, (b) 22.1 g

Solution : Given,

Mass of iron = 15.5 g

Molar mass of iron = 56 g/mole

Molar mass of Fe_2O_3 = 160 g/mole

First we have to calculate the moles of iron.

\text{Moles of Fe}=\frac{\text{Mass of Fe}}{\text{Molar mass of Fe}}=\frac{15.5g}{56g/mole}=0.276moles

Now we have to calculate the moles of Fe_2O_3.

The balanced reaction is,

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2

From the balanced reaction, we conclude that

As, 2 moles of iron obtained from 1 mole of Fe_2O_3

So, 0.276 moles of iron obtained from \frac{0.276}{2}=0.138 mole of Fe_2O_3

Now we have to calculate the mass of Fe_2O_3

\text{Mass of }Fe_2O_3=\text{Moles of }Fe_2O_3\times \text{Molar mass of }Fe_2O_3

\text{Mass of }Fe_2O_3=(0.138mole)\times (160g/mole)=22.08g=22.1g

Therefore, the amount of Fe_2O_3 required are, 22.1 grams.

6 0
3 years ago
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