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Colt1911 [192]
3 years ago
15

john made two candles in the shape of rectangular prisms. The first candle is 12cm high, 4 cm long, and 6 cm wide. The second ca

ndle is 4 cm higher, but has the same length and width. How much additional wax was needed to make the taller candle?
Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

96cm^3

Step-by-step explanation:

To determine how much additional wax was needed to make the taller candle, we determine the volume of each of the candles and find the difference in their volumes

<u>First Candle</u>

  • Height=12cm
  • Length=4 cm
  • Width= 6 cm

Volume=Height X Length X Width

=12 X 4 X 6

=288cm^3

<u>Second Candle</u>

The second candle is 4cm higher

  • Height=12+4=16cm
  • Length=4 cm
  • Width= 6 cm

Volume=Height X Length X Width

=16 X 4 X 6

=384cm^3

Difference in Volume = 384-288 =96cm^3

Therefore, 96cm^3 of additional wax was used to make the second candle.

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A restaurant has a total of 30 tables which are of two
Anna007 [38]

Answer:

Total number of tables of first type       = 23.

Total number of tables of second type = 7

Step-by-step explanation:

It is given that there are 30 tables in total and there are two types of tables.

Let's call the two seat tables, the first type as x and the second type as y.

∴                                             x + y = 30                        ......(1)

Also a total number of 81 people are seated. Therefore, 2x number of people would be seated on the the first type and 5y on the second type. Hence the equation becomes:

                                            2x + 5y = 81                        .....(2)

To solve (1) & (2) Multiply (1) by 2 and subtract, we get:

                                                      y = 7

Substituting y = 7 in (1), we get x = 23.

∴ The number of tables of first kind         = 23

  The number of tables of second kind   = 7

3 0
3 years ago
30 pts.!! Which expression is equivalent to (4√5^3)^1/2? <br>5^3/8 <br>5^6 5^16/3 <br>5^2/3
vampirchik [111]

it would be 5^6 5^16/

5 0
4 years ago
5 times a number is 110 less than 7 times that number
Nitella [24]

Answer:

55

Step-by-step explanation:

let the number=x

5x=7x-110

7x-5x=110

2x=110

x=110/2=55

3 0
3 years ago
Dylan is evaluating the expression 13+19+7+10 . At one step in his work, Dylan rewrites the equation as 13+7+19+10 Which propert
zhuklara [117]
By looking at the current state of the question, the answer is associative property because that seems to be the only option present

3 0
4 years ago
Read 2 more answers
A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s
quester [9]

Answer:

a) P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

b) p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

c) L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

d) L_q =\frac{20^2}{30(30-20)}=1.333 people

e) W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

f) W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

p_x represent the probability that the employee is busy

L_s represent the average number of people receiving and waiting to receive some information

L_q represent the average number of people waiting in line to get some information

W_s represent the average time a person seeking information spends in the system

W_q represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}

And in order to find the probability we can do this:

P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

L_s= \frac{\lambda}{\lambda -\mu}

And replacing we got:

L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}

And replacing we got this:

L_q =\frac{20^2}{30(30-20)}=1.333 people

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

6 0
3 years ago
Read 2 more answers
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