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Oxana [17]
3 years ago
15

In a percentage composition investigation a compound was decomposed into its elements: 20.0 g of calcium, 6.0 g of carbon, and 2

4.0 g of oxygen. Determine the percentage composition of this compound
Chemistry
1 answer:
inysia [295]3 years ago
3 0

The percentage composition of this compound : 40%Ca, 12%C and 48%O

<h3>Further explanation</h3>

Given

20.0 g of calcium,

6.0 g of carbon,

and 24.0 g of oxygen.

Required

The percentage composition

Solution

Total mass of compound :

=mass calcium + mass carbon + mass oxygen

=20 g + 6 g + 24 g

=50 g

Percentage composition :

  • Ca-calcium

\tt \dfrac{20}{50}\times 100\%=40\%

  • C-carbon

\tt \dfrac{6}{50}\times 100\%=12\%

  • O-oxygen

\tt \dfrac{24}{50}\times 100\%=48\%

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Answer:

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Answer:

<em>The correct option is a) Precipitate: silver sulfate </em>

<em> </em>

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Explanation:

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What is the density of a object whose dimensions are 5.54
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The object with dimensions 5.54\ cm \times 10.6\ cm \times 199\ cm and with mass 250.6 g will have a density equal to 0.02144\ g/cm^3.

<h3><u>Explanation:</u></h3>

<u>Given:</u>

Dimensions of the object = 5.54\ cm \times 10.6\ cm \times 199\ cm

length = l = 5.54 cm

width = w = 10.6 cm

height = h = 199 cm

Mass of the object = m = 250.6 g

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The relation between density, mass and volume of any object is given by:

Density = \frac{ Mass }{Volume}

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