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3 years ago

Please help me ill give brainiest

Chemistry

2 answers:

V125BC [204]3 years ago

6 0

Reaction on the left product on the right

lyudmila [28]3 years ago

5 0

Your reactants are on the left side and your product is on the right side

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What mass of lif is contained in 18.66 g of a 20.0% by mass solution of lif in water?

aev [14]

Answer is: mass of lithium fluoride is 3,732 grams.
m(solution) = 18,66 g.
ω(solution) = 20% = 20% ÷ 100% = 0,2.
m(LiF) = ?
ω(solution) = m(LiF) ÷ m(solution).
m(LiF) = ω(solution) · m(solution).
m(LiF) = 0,2 · 18,66 g.
m(LiF) = 3,732 g.

7 0

3 years ago

Chromium has four naturally occuring isotopes. Cr-50 (mass of 49.946 amu and 4.35% abundance); Cr-52 (mass of 51.941 amu and 83.

Lemur [1.5K]

Answer:

B) 52.000 amu.

Explanation:

An element can have differing numbers of neutrons in its nucleus, but it always has the same number of protons. The versions of an element with different neutrons have different masses and are called isotopes.

The average atomic mass for an element is calculated by summing the masses of the element’s isotopes, each multiplied by its natural abundance on Earth.

Average atomic mass of P = ∑(Isotope mass)(its abundance)

∴ Average atomic mass of Cr = (Cr-50 mass)(its abundance) + (Cr-52 mass)(its abundance) + (Cr-53 mass)(its abundance) + (Cr-54 mass)(its abundance)

Abundance of isotope = % of the isotope / 100.

∴ Average atomic mass of Cr = (49.946 amu)(0.0435) + (51.941 amu)(0.8379) + (52.941 amu)(0.095) + (53.939 amu)(0.0236) = 52.000 amu.

So, the right choice is: B) 52.000 amu.

8 0

4 years ago

Matter with no definite shape or volume

MAVERICK [17]

Answer:

Gases have no definite shape or volume.

7 0

3 years ago

WHAT MASS OF 1,1 DICHLOROEHTANE MUST BE MIXED WITH 100G OF 1,1 DICHLOROTETRAFLUOROEHTANE TO GIVE A SOLUTION WITH VAPOR PRESSURE

vaieri [72.5K]

This is an incomplete question.

The complete question is:

1,1-dichlorotetrafluoroethane, CF3CCL2F, has a vapor pressure of 228 torr. What mass of 1,1-dichloroethane must be mixed with 100.0 g of 1,1-dichlorotetrafluoroethane to give a solution with vapor pressure 157 torr at 25 degrees celsius?

Answer: 46.9 g of 1,1 dichloroethane must be fixed with 100 g of 1,1 dichlorotetrafluoroethane to give a solution with vapor pressure of 157 torr at $25^0C$

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

$\frac{p^o-p_s}{p^o}=i\times x_2$

where,

$\frac{p^o-p_s}{p^o}$ = relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

$x_2$ = mole fraction of solute

= $\frac{\text {moles of solute}}{\text {total moles}}$

Given : x g of solute is present in 100 g of solvent

moles of solute (1,1 DICHLOROEHTANE) = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{xg}{98.96g/mol}moles$

moles of solvent (1,1 DICHLOROTETRAFLUOROEHTANE ) = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{100g}{170.92g/mol}=0.58moles$

Total moles = moles of solute + moles of solvent = $\frac{xg}{98.96g/mol}+0.58$

$x_2$ = mole fraction of solute = $\frac{\frac{xg}{98.96g/mol}}{\frac{xg}{98.96g/mol}+0.58}$

$\frac{228-157}{157}=1\times \frac{\frac{xg}{98.96g/mol}}{\frac{xg}{98.96g/mol}+0.58}$

$0.45=1\times \frac{\frac{xg}{98.96g/mol}}{\frac{xg}{98.96g/mol}+0.58}$

$x=46.9g$

Thus 46.9 g of 1,1 dichloroethane must be fixed with 100 g of 1,1 dichlorotetrafluoroethane to give a solution with vapor pressure of 157 torr at $25^0C$

5 0

4 years ago

A volume of 5.0 L of gas at a temperature of 25°C is cooled to a temperature of -120°C at constant pressure. What is the new vol

lorasvet [3.4K]

V1 = 5L = 5000ml V2 = ?
T1 = 25°C = 25+273 T2 = -120°C
= 297K = -120+273
= 153K
By Charles Law,
V1/T1 = V2/T2
5000/297 = V2/153
By solving,
V2 = 2.576L

5 0

3 years ago