Question

ODIO POD

Answer 1

Answer:

$\boxed{\text{40 mol Al}}$

Explanation:

            Al₂O₃ ⟶ 2Al + 3O₂

n/mol:     20

$\text{Moles of Al} = \text{20 mol Al _{2} O _{3} }\times \dfrac{\text{2 mol Al}}{\text{1 mol Al _{2} O _{3} }}= \textbf{40 mol Al}\\\text{You can produce }\boxed{\textbf{40 mol Al}}$